solution:
Z1 = 5(cos25˚+isin25˚)
Z2 = 2(cos80˚+isin80˚)
Z1.Z2 = 5(cos25˚+isin25˚). 2(cos80˚+isin80˚)
Z1.Z2 = 10{(cos25˚cos80˚ + isin25˚cos80˚+i^2sin25˚sin80˚) }
Z1.Z2 =10{(cos25˚cos80˚- sin25˚sin80˚+ i(cos25˚sin80˚+sin25˚cos80˚))}
(i^2 = -1)
Cos(A+B) = cosAcosB – sinAsinB
Sin(A+B) = sinAcosB + cosAsinB
Z1.Z2 = 10(cos(25˚+80˚) +isin(25˚+80˚)
Z1.Z2 = 10(cos105˚+ isin105˚)
X² - 7x + 10 = 0
Let's factor out the equation first.
x² - 7x + 10
x -2
x -5
This factoring of (x-2)(x-5) fit the equation.
(x-2)(x-5) = 0
One of the factors must equal 0 as to equal zero.
Either x - 2 = 0 or x - 5 = 0
x - 2 = 0
x = 2
x - 5 = 0
x = 5
The two answers are x = 2 or x = 5. Hope this helps!
amount after 2 years = 6000(1 + (0.04/12))^24 = 6498.86
Answer: 28 in.
Step-by-step explanation:
its simple
Answer:
C
Step-by-step explanation:
The area of the wall hanging shown in blue is the area of the square 8 by 8 minus the area of the cutout. Notice the cutout is a triangle? To find the total area, subtract the area of the triangle from the square.
The square has the sides 8 by 8 and its area is found as A = 8*8 = 64.
The triangle measures 4 inches by 4 inches. The area is found as A = 1/2*4*4 = 8.
Subtract the two areas.
64 - 8 = 56
