Question

Evaluate 3^√343 + 3/4 3^√-8. -5 1/2 5 1/2 8 1/2

Answer 1

The correct option is B i.e. $5\frac{1}{2}$.

Step-by-step explanation:

We have the following expression , $\sqrt[3]{343} + \frac{3}{4} \sqrt[3]{-8}$ . As we see the options there aren't in iota or in complex number hence, the correct expression to evaluate must be , $\sqrt[3]{343} + \frac{-3}{4} \sqrt[3]{8}$ . Let's evaluate the expression to simplify:

$\sqrt[3]{343} + \frac{-3}{4} \sqrt[3]{8}$  , its known that $\sqrt[3]{343} = 7$ and $\sqrt[3]{8} = 2$.

⇒ $\sqrt[3]{343} + \frac{-3}{4} \sqrt[3]{8}$

⇒ $\sqrt[3]{343} - \frac{3}{4} \sqrt[3]{8}$

⇒ $7 - \frac{3}{4}(2)$

⇒ $7 - \frac{3}{2}$

⇒ $\frac{14-3}{2}$

⇒ $\frac{11}{2} = 5\frac{1}{2}$

Therefore, the correct option is B i.e. $5\frac{1}{2}$.