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vovangra [49]
3 years ago
12

12. Which of the following is the value of x needed to make the equation

Mathematics
1 answer:
patriot [66]3 years ago
6 0

Answer:

it will be c, x=8.5

Step-by-step explanation:

-18+4x=-4x+50

4x+4x=18+50

8x=68

x=8.5

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Examine the equation below. Use it to answer question 54.
sashaice [31]

D= it's is true because ox equals 3*2x

8 0
3 years ago
A man travels 320 miles in 8 hours. If he continues at the same rate, how many miles will he
evablogger [386]

Answer: 80 miles

Step-by-step explanation:

320miles/8hours= 40mph

40mph=xmiles/2hrs

40*2= 80 miles

8 0
3 years ago
1. What is the measure of angle x? O 60° O 90° O 45° O 30°​
True [87]

Answer:

Angle x= 60°

Step-by-step explanation:

For the triangle HIL, you're going to add 30+90=120

Angles in a triangle add up to 180.

So, therefore,

180-120=60   so angle L must equal 60.

HJ is a straight line and angles in a straight line add up to 180.

180-90=90

Angle JIL is equal to 90.

To find y you add 90+45 which equals 135.

Again, angles in a triangle add up to 180.

180-135=45

So,

y = 45

Now we are told that IJK is a right angle and that we are given that IJL is 45. 45 is half of 90 so LJK must be 45.

To find angle JLK we must add angle L and angle y.

60+45=105

Angles in a straight line add up to 180. So,

180-105=75

75 = Angle JLK

75+45=120

Angles in a triangle add up to 180 so,

180-120= 60

Angle x= 60°

Hope this helped, if so please award me with the brainliest if possible. If you require further assistance from me comment below! :)

5 0
2 years ago
The demand function for q units of a product at $p per unit is given by p(q + 3)2 = 100,000. Find the rate of change of quantity
wariber [46]

Answer:

-0.625 unit

Step-by-step explanation:

Given that:

p(q+3)^2 = 100, 000

where;

p = price

q = quantity

To find the rate of change of quantity (q) with respect to price (p) we go by the differentiation

(q+3)^2\frac{dp}{dp} +p^2(q+3)\frac{dq}{dp}=0

(q+3)^2 +p^2(q+3)\frac{dq}{dp}=0

\frac{dq}{dp}=\frac{-(q+3)}{2p}

when P =40

Then 4(q+3)² = 100, 000

(q+3)² = \frac{100,000}{4}

(q+3)² = 25,000

(q+3) = \sqrt{2500}

q+ 3 = 50

q = 50 -3

q = 47

NOW; \frac{dq}{dp}=\frac{-(q+3)}{2p}

\frac{dq}{dp}=\frac{-(47+3)}{2*40}

\frac{dq}{dp}=\frac{-47-3}{2*40}

\frac{dq}{dp}=\frac{-50}{80}

\frac{dq}{dp}=-0.625

Thus, the rate of change of quantity with respect to price when p = $40 is -0.625 unit.

8 0
4 years ago
What is x- 2 1/2 = 6 3/4. pls help
MAXImum [283]
X= 9 1/4 or 9.25 in decimal form
8 0
3 years ago
Read 2 more answers
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