Answer:
was this the whole question cause it depends on what the plane is
Step-by-step explanation:
Consider the triangle (<em>in </em><em>which </em><em>angle</em><em>4</em><em> </em><em>is </em><em>present</em>)
by angle sum property,
20 + 40 + angle4 = 180
60 + angle4 = 180
angle4 = 180 - 60
angle4 = 120
Also,
angle2 = 120 (vertically opposite angles)
angle1 + angle2 = 180 (linear pair)
angle1 + 120 = 180
angle1 = 180 - 120
angle1 = 60
All of the numbers are the mode, so it is
1982, 1988, 1989, 1994, 1995, 2005
Answer:
Area of triangle = 144 sq.in
Area of rectangle = 312 sq.in
Area of whole figure = 456 sq.in
Step-by-step explanation:
area of truangle =
- 1/2 × 24 × 12
- 12 × 12
- 144
area of rectangle =
area of whole fig. = 312 + 144 = 456 sq.in
Do you mean like where you find one for 3 and 9? if so it's for 3 is 1 and for 9 is 3