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AlexFokin [52]
3 years ago
6

The amount of time it takes Isabella to wait for the bus is continuous and uniformly distributed between 3 minutes and 15 minute

s. What is the probability that it takes Isabella more than 11 minutes to wait for the bus?
Mathematics
1 answer:
madam [21]3 years ago
4 0

Answer:

33.33% probability that it takes Isabella more than 11 minutes to wait for the bus

Step-by-step explanation:

An uniform probability is a case of probability in which each outcome is equally as likely.

For this situation, we have a lower limit of the distribution that we call a and an upper limit that we call b.

The probability that we find a value X lower than x is given by the following formula.

P(X \leq x) = \frac{x - a}{b-a}

For this problem, we have that:

Uniformly distributed between 3 minutes and 15 minutes:

So a = 3, b = 15

What is the probability that it takes Isabella more than 11 minutes to wait for the bus?

Either she has to wait 11 or less minutes for the bus, or she has to wait more than 11 minutes. The sum of these probabilities is 1. So

P(X \leq 11) + P(X > 11) = 1

We want P(X > 11). So

P(X > 11) = 1 - P(X \leq 11) = 1 - \frac{11 - 3}{15 - 3} = 0.3333

33.33% probability that it takes Isabella more than 11 minutes to wait for the bus

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Question;

1) The shaded plants set has greater variability because more data is clustered around the median.

2) The sets are equally variable because the ranges of the data sets are equal.

3) The full sun plants set has greater variability because the IQR for full sun plants is greater.

Answer:

The correct option is;

3) The full sun plants set has greater variability because the IQR for full sun plants is greater

Step-by-step explanation:

To answer the question, we present the dot plot as follows;

Heights of Shaded plants (inches)

          0       4      3       2      0       0             1

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We calculate the five numbers as follows;

Max = 4.5

Min = 2

1st quartile = (10+1)/4 th term = 3

2nd quartile (Median) = (10+1)/2 th term = 4

3rd quartile = 3×(10+1)/4 th term = 4.5

Interquatile range (IQR) = Q₃ - Q₁ = 4.5 - 3 = 1.5

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