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vazorg [7]
3 years ago
12

Could you help me with my math?

Mathematics
1 answer:
monitta3 years ago
5 0

A and D are the best examples here of scaled copies. Only the relative size changes in a scale copy, not the proportions. In D every side is twice as large as the corresponding side of A.

B is "no good," because the its proportions differ, if not its basic shape, when we look at A. Notice how the "fingers" of B are long and narrow, unlike the "fingers" of A.

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4 0
3 years ago
The sum of twice a number and 13 is 75
Nina [5.8K]
So what they are saying is the sum of 2x +13=75
Therefore we can just solve for 2x, our unknown value.
2x+13=75 now subtract 13 and divide by 2 from both sides of equation to not change the equation
x+13-13=75-13
This leaves us with
x=(75-13)/2=31 therefore x=31 or our unknown value is 31.

I hope this helped. Any questions please just ask. Thank you.
3 0
4 years ago
Help plssssssss, thank you
IRINA_888 [86]

Answer:

x = 14

Step-by-step explanation:

Given

- \frac{1}{5}(x - 4) = - 2

Multiply both sides by 5 to eliminate the fraction

- (x - 4) = - 10 ← distribute parenthesis by - 1

- x + 4 = - 10 ( subtract 4 from both sides )

- x = - 14 ( multiply both sides by - 1 )

x = 14

6 0
4 years ago
If a leg of a 45-45-90 triangle is 11 then the hypotenuse is...
iragen [17]

Answer:

c)11√2

Step-by-step explanation:

Given that two of the angles are equal ,each measuring 45 degrees then two legs will be equal as well each measuring 11 units. We have a right angled triangle with two sides given and we are required to determine the hypotenuse. We use Pythagoras theorem;

hypotenuse^2 = 11^2 + 11^2

hypotenuse ^2 = 242

hypotenuse = \sqrt{242}

hypotenuse = 11\sqrt{2}

3 0
4 years ago
Read 2 more answers
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You would graph the equation f(x) = –x + 3 for input values less than 2. There would be an open circle at the point (2, 1) since the domain for the first piece does not include 2. You would then graph a horizontal line at f(x) = 3 for input values between 2 and 4. There would be a closed circle at (2, 3) and an open circle at (4, 3). Last, you would graph f(x) = 4 – 9x for input values greater than or equal to 4. There would be a closed circle at the point (4, –4) since 4 is in the domain of the third piece.

8 0
3 years ago
Read 2 more answers
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