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2 years ago

Martin wants to use coordinate geometry to prove that the opposite sides of

Mathematics

1 answer:

romanna [79]2 years ago

4 0

The correct answer is option A which is the distance between A and D will be AD = $\sqrt{(0-0)^2-(b-0)^2}=\sqrt{b^2}=b$ .

<h3>What is coordinate geometry?</h3>

A coordinate plane is a 2D plane which is formed by the intersection of two perpendicular lines known as the x-axis and y-axis.

The formula utilised to find the distance between two points is;-

X = $\sqrt{(x_2-x_1)^2+(y_2-y_1)^2$

We have the coordinates of the point A = (0, 0) and D is (0, b).By applying the formula to find the distance between A and D.

AD = $\sqrt{(0-0)^2-(b-0)^2}=\sqrt{b^2}=b$ .

Therefore the correct answer is option A which is the distance between A and D will be AD = $\sqrt{(0-0)^2-(b-0)^2}=\sqrt{b^2}=b$ .

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A stick 43 inches long is broken into two pieces, so that one piece is twice as long as the other. How long are the two pieces?

allsm [11]

Answer:

One piece is $\frac{43}{3}$ inches and another piece is $\frac{86}{3}$ inches

Step-by-step explanation:

Let smaller piece length be $s$

Let larger piece length be $l$

Since total of two pieces is 43, we can write:

$s+l=43$

Also, one piece is twice as long as the other (so longer piece is definitely twice as the short piece), we can write:

$l=2s$

<em>Substituting equation 2 into equation one, we can solve for s:</em>

$s+l=43\\s+(2s)=43\\3s=43\\s=\frac{43}{3}$

<em>Thus longer piece is:</em>

$l=2s=2(\frac{43}{3})=\frac{86}{3}$

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3 years ago

A)<br> Identify all x-values not in the domain of<br> y=(x² – 4x²) / (3x² - 6x – 24)

True [87]

Answer:

x ≠ 4 or -2

Step-by-step explanation:

the denominator cannot be zero, so factor the bottom equation to get the zeros and those are the domain restrictions.

3x^2 - 6x - 24 ≠ 0

3(x^2 - 2x - 8) ≠ 0 (factor out a 3)

3(x - 4)(x + 2) ≠ 0 (factor equation)

x ≠ 4, x ≠ -2 (use zero product property to find zeros)

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3 years ago

Can someone help me find the annulus of the shaded area? much appreciated

Dimas [21]

Answer:

34.83

Step-by-step explanation:

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2 years ago

Prove that 1/sec0-tan0= sec0+tan0

Leviafan [203]

Answer:

Step-by-step explanation:

$\text{LHS}=\frac{1}{\sec \theta-\tan \theta}\\=\frac{\sec \theta+\tan \theta}{(\sec \theta-\tan \theta)(\sec \theta+\tan \theta)}\\=\frac{\sec \theta+\tan \theta}{\sec^{2} \theta-\tan^{2} \theta}\\=\frac{\sec \theta+\tan \theta}{1}\\=\sec \theta+\tan \theta\\=\text{RHS}$

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2 years ago

To edit a manuscript, Miguel charges 12 dollars per hour for the first 4 hours and 15 dollars per hour after the first 4 hours.

aleksley [76]

Answer:

C = 12 + 15(x - 4)

C = 15x - 48

Step-by-step explanation:

Let the number of hours = t

The total amount Miguel earns =

To edit a manuscript, Miguel charges 12 dollars per hour for the first 4 hours and 15 dollars per hour after the first 4 hours.

C = 12 + 15(x - 4)

Expand the t

C = 12 + 15x - 60

C = 15x - 48

Therefore, an expression for the amount, in dollars, Miguel charges if it takes him t hours to edit a manuscript, where t>4 is given as:

C = 15x - 48

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3 years ago