distance between two points is [(x2-x1)^2 +(y2-y1)^2]^1/2
I.e,[{5-1)^2+(0-3)^2]^1/2
[16+9]^1/2
[25]^1/2
5
Answer:
f^-1(x)=100-x
Step-by-step explanation:
Answer:
Step-by-step explanation:
Given that:
The differential equation; 
The above equation can be better expressed as:

The pattern of the normalized differential equation can be represented as:
y'' + p(x)y' + q(x) y = 0
This implies that:



Also;


From p(x) and q(x); we will realize that the zeroes of (x+2)(x-2)² = ±2
When x = - 2






Hence, one (1) of them is non-analytical at x = 2.
Thus, x = 2 is an irregular singular point.
Answer:
First, we need to set up a (y−k)^2=4p(x−h). After plugging in all of your values, you would get (x-5)^2=-4(y-1). Now, we need to solve in terms of y by dividing each side by the factors that don't contain the variable
Step-by-step explanation:
Answer:
d the other equations the total is 35. this one the total would be 55