How do you do 720 divided by 10 with the exponet of 3

2 answers:

4 0

If you mean 720/10^3, you do 10*10*10. This equals 1000. Now, do 720/1000. This is 0.72, or 72/100, which is your answer.

Scrat [10]3 years ago

3 0

10^3 = 10 * 10 * 10 = 1,000
720 / 1,000= 0.72
72/100 because .75 is in hundredths place
Simplify 72/100 = 18/25
Final answer is 18/25

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Given A = {x | x < 1}, B = {x | x ≥ 5}, and C = {x | x = 5}, match the following items. 1. A B Ø 2. A C {x | x ≥ 5} 3. B C {x

ivann1987 [24]

Answer:

The matching is shown below.

Step-by-step explanation:

The given sets are defined as

A = {x | x < 1}

It means all the values of x which are less than 1.

B = {x | x ≥ 5}

It means all the values of x which are greater than or equal to 5.

C = {x | x = 5}

It means all the value of x is 5.

Union of two sets contains all the elements of both sets.

Intersection of two sets contains only common elements of both sets.

The matching is shown below.

Sets Correct value

1. A ∪ B {x | x < 1 or x ≥ 5}

2. A ∪ C {x | x < 1 or x = 5}

3. B ∪ C {x | x ≥ 5}

4. A ∩ B Ø

5. B ∩ C {x | x = 5}

6 0

3 years ago

I need help w/ this!! thank you

Fittoniya [83]

<h3>Answer:</h3>

$\boxed{\pink{\sf \leadsto Yes \ there \ is \ a \ solution \ of \ the \ given \ inequality .}}$

<h3>Step-by-step explanation:</h3>

A inequality is given to us and we need to convert it into standard form and see whether if it has a solution . So let's solve the inequality.

The inequality given to us is :-

$\bf\implies |2y + 3 | - 1 \leq 0 \\\\\bf\implies |2y+3|\leq 1 \\\\\bf\implies (|2y+3|)^2 \leq 1^2 \\\\\bf\implies (2y+3)^2 \leq 1 \\\\\bf\implies (2y)^2+3^2+2(2y)(3) \leq 1 \\\\\bf\implies 4y^2+9+12y - 1 \leq 0 \\\\\bf\implies 4y^2+12y+8 \leq 0 \\\\\bf\implies 4( y^2 + 3y + 2 ) \leq 0 \\\\\bf\implies y^2+3y +2 \leq 0 \:\:\bigg\lgroup \purple{\bf Standard \ form \ of \ inequality }\bigg\rgroup \\\\\bf\implies y^2y+2y+y+2 \leq 0 \\\\\bf\implies y(y+2)+1(y+2)\leq 0 \\\\\bf\implies ( y+2)(y+1)\leq 0 \\\\\bf\implies \boxed{\red{\bf y \leq (-2) , (-1) }}$