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Olenka [21]
2 years ago
10

Calculate the area of the shape. CAN ANYONE HELP ???

Mathematics
2 answers:
lisov135 [29]2 years ago
7 0

Answer: 4+3+3+4

Step-by-step explanation:add first 4 +3

Kazeer [188]2 years ago
7 0

Answer:

81cm²

Step-by-step explanation:

So lets take the top shape as T1 and the bottom one as T2.

So for T2,

It is a square so the area is side×side

=5×5=25cm²

In T2,

The shape is a rectangle so the area=l×b

the length is not directly given, it is =4+5+5=14cm

Area=14×4

A=56cm²

Now the total area= Area of T1+ Area of T2

= 25+56= <em><u>81cm²</u></em>

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Archy [21]

(a) If the particle's position (measured with some unit) at time <em>t</em> is given by <em>s(t)</em>, where

s(t) = \dfrac{5t}{t^2+11}\,\mathrm{units}

then the velocity at time <em>t</em>, <em>v(t)</em>, is given by the derivative of <em>s(t)</em>,

v(t) = \dfrac{\mathrm ds}{\mathrm dt} = \dfrac{5(t^2+11)-5t(2t)}{(t^2+11)^2} = \boxed{\dfrac{-5t^2+55}{(t^2+11)^2}\,\dfrac{\rm units}{\rm s}}

(b) The velocity after 3 seconds is

v(3) = \dfrac{-5\cdot3^2+55}{(3^2+11)^2} = \dfrac{1}{40}\dfrac{\rm units}{\rm s} = \boxed{0.025\dfrac{\rm units}{\rm s}}

(c) The particle is at rest when its velocity is zero:

\dfrac{-5t^2+55}{(t^2+11)^2} = 0 \implies -5t^2+55 = 0 \implies t^2 = 11 \implies t=\pm\sqrt{11}\,\mathrm s \imples t \approx \boxed{3.317\,\mathrm s}

(d) The particle is moving in the positive direction when its position is increasing, or equivalently when its velocity is positive:

\dfrac{-5t^2+55}{(t^2+11)^2} > 0 \implies -5t^2+55>0 \implies -5t^2>-55 \implies t^2 < 11 \implies |t|

In interval notation, this happens for <em>t</em> in the interval (0, √11) or approximately (0, 3.317) s.

(e) The total distance traveled is given by the definite integral,

\displaystyle \int_0^8 |v(t)|\,\mathrm dt

By definition of absolute value, we have

|v(t)| = \begin{cases}v(t) & \text{if }v(t)\ge0 \\ -v(t) & \text{if }v(t)

In part (d), we've shown that <em>v(t)</em> > 0 when -√11 < <em>t</em> < √11, so we split up the integral at <em>t</em> = √11 as

\displaystyle \int_0^8 |v(t)|\,\mathrm dt = \int_0^{\sqrt{11}}v(t)\,\mathrm dt - \int_{\sqrt{11}}^8 v(t)\,\mathrm dt

and by the fundamental theorem of calculus, since we know <em>v(t)</em> is the derivative of <em>s(t)</em>, this reduces to

s(\sqrt{11})-s(0) - s(8) + s(\sqrt{11)) = 2s(\sqrt{11})-s(0)-s(8) = \dfrac5{\sqrt{11}}-0 - \dfrac8{15} \approx 0.974\,\mathrm{units}

7 0
2 years ago
Which equation is modeled below?
masha68 [24]

Answer:

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Step-by-step explanation:

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5 0
3 years ago
Need help with this question
goldfiish [28.3K]

Answer:

x = 12

Step-by-step explanation:

Complementary angles add up to have a sum of 90 degrees. We can create an equation and solve for x.

3x + 6x - 18 = 90

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9x - 18 = 90

~Add 18 to both sides

9x = 108

~Divide 9 to both sides

x = 12

Best of Luck!

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2 years ago
Simplify the expression 5/x-2y5
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5x-y10 We're basically just multiplying the 5 by x and the y by 5 and -2.

(5/x= 5x) + (y/-2/-5)

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