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Olenka [21]
2 years ago
10

Calculate the area of the shape. CAN ANYONE HELP ???

Mathematics
2 answers:
lisov135 [29]2 years ago
7 0

Answer: 4+3+3+4

Step-by-step explanation:add first 4 +3

Kazeer [188]2 years ago
7 0

Answer:

81cm²

Step-by-step explanation:

So lets take the top shape as T1 and the bottom one as T2.

So for T2,

It is a square so the area is side×side

=5×5=25cm²

In T2,

The shape is a rectangle so the area=l×b

the length is not directly given, it is =4+5+5=14cm

Area=14×4

A=56cm²

Now the total area= Area of T1+ Area of T2

= 25+56= <em><u>81cm²</u></em>

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Daniel [21]
<h3>Answer:  $5.16</h3>

==================================================

Work Shown:

72% = 72/100 = 0.72

72% of $3.00 = 0.72*3.00 = 2.16

The price increases by $2.16 to get the final answer of 3.00+2.16 = 5.16 dollars

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We can find this answer through this alternative route:

1.72*3 = 5.16

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Therefore, using the Pythagorean identities:
<span>sin(\theta) = \frac{12}{20} = \boxed{\frac{3}{5}} \\\ cos(\theta) = \frac{16}{20} = \boxed{\frac{4}{5}} \\\ tan(\theta) = \frac{12}{16} = \boxed{\frac{3}{4}} </span>
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19. Given that angle BFC = 58°. Angle BXG = 48° and angle CBF 22 Find () 2BGX (iv) BCG (i) 2BGF (iv) ZBFG (ii) BCF H EE 58 48° D
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The unknown angles in the cyclic quadrilateral is as follows:

∠BGX = 74° (sum of angles in a triangle)

∠BGF = 180° (opposite angles of cyclic quadrilateral are supplementary)

∠BCF = 100°(sum of angles in a triangle)

∠BCG  = 26°

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<h3>Cyclic Quadrilateral</h3>

A cyclic quadrilateral has all its angles equal to 360 degrees. The sum of angles in a cyclic quadrilateral is equals to 360 degrees.

Let's find the missing angles as follows:

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∠BCF = 180 - 22 - 58 = 100°(sum of angles in a triangle)

∠BCG = 100 - 74 = 26°

∠BFG ≅ CBF = 22°(alternate angles)

learn more on angles here: brainly.com/question/19430381

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