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ser-zykov [4K]
3 years ago
14

Duru has an ice-cream stand, which she opens on days that are forecasted to be warmer than 10°C.

Mathematics
1 answer:
Amanda [17]3 years ago
8 0

Answer:

P(c(t)) =  20t-120

Step-by-step explanation:

Given

P(n) = 2n - 20

C(t) = 50 + 10(t - 10)

Required

Determine P(C(t))

The implication of the question is to solve for P(C(t))

Given that

C(t) = 50 + 10(t - 10) and P(n) = 2n - 20

P(c(t)) would be

P(c(t)) = 2(50 + 10(t - 10)) - 20

P(c(t)) = 2(50 + 10t - 100) - 20

Collect Like Terms

P(c(t)) = 2(50  - 100+ 10t) - 20

P(c(t)) = 2(-50+ 10t) - 20

Open Bracket

P(c(t)) = -100+ 20t - 20

Collect Like Terms

P(c(t)) =  20t-100 - 20

P(c(t)) =  20t-120

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The given line passes through the points and (-4, -3) and (4, 1).
Debora [2.8K]

Answer:

The equation of the line is y - 3 = -2(x + 4)

Step-by-step explanation:

* Lets explain how to solve the problem

- The slope of the line which passes through the points (x1 , y1) and

  (x2 , y2) is m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}

- The product of the slopes of the perpendicular lines = -1

- That means if the slope of a line is m then the slope of the

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- The point-slope of the equation is y - y_{1}=m(x - x_{1})

* lets solve the problem

∵ A given line passes through points (-4 , -3) and (4 , 1)

∴ x1 = -4 , x2 = 4 and y1 = -3 , y2 = 1

∴ The slope of the line m=\frac{1-(-3)}{4-(-4)}=\frac{1+3}{4+4}=\frac{4}{8}=\frac{1}{2}

- The slope of the line perpendicular to this line is -1/m

∵ m = 1/2

∴ The slope of the perpendicular line is -2

- Lets find the equation of the line whose slope is -2 and passes

 through point (-4 , 3)

∵ x1 = -4 , y1 = 3

∵ m = -2

∵ y - y1 = m(x - x1)

∴ y - 3 = -2(x - (-4))

∴ y - 3 = -2(x + 4)

* The equation of the line is y - 3 = -2(x + 4)

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