I would assume this to be equal to y⁴ ₓ y⁵
= y⁴ ⁺ ⁵, By law of indices.
= y⁹
I hope this helped.
Answer:
y= -x+7, b= sqrt(2P/a), c=3P^2-b
Step-by-step explanation:
First, make a table regarding both of the equations. You will eventually find out that both lines intersect at the point (2, 5) after you find the points on the table. From there, subtract x from both sides in the equation x + y = 2. You will get y = -x + 2. Since they said the line was parallel, find a line that has the slope of negative one. Since we know that this line intersects the point in which the first two lines intersect, we know that the y-intercept will be 7. The equation of the line would be y=-x+7.
Multiply both sides by 2. Then, divide both sides by a to get b^2=(2P/a). Take the square root to get the value of b, which is sqrt(2P/a).
Square both sides of the equation to get P^2=(b+c)/3. Cross multiply to get 3P^2=b+c. Subtract b from both sides to get c=3P^2-b.
Answer:
Equation of midsegment line: y = (-1/4)x + 2.
Step-by-step explanation:
If the parallel sides of a trapezoid are contained by the lines:-
y = (-1/4)x +5 and y = (-1/4)x - 1
Midsegment of any trapezoid is the line segment
1. that is parallel to pair of parallel side of trapezoid and
2. that passes through the middle of the trapezoid and cuts the other two sides into equal-half.
It means the midsegment would have same slope as the parallel lines and y-intercept would be in the middle of intercepts of parallel lines.
So y = mx + b
where m = -1/4 and b = (5 - 1)/2 = 4/2 = 2.
Hence, the equation of midsegment would be y = (-1/4)x + 2.
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