Tan 49 = x/400 <br> please solve

Theo borrows $8,000 for college expenses. He will pay a total of $10,280 after 6 years. What percent of interest did Theo pay?

goldenfox [79]

9514 1404 393

Answer:

4.75%

Step-by-step explanation:

When simple interest is charged, the payback amount is ...

A = P(1 +rt) . . . . for annual rate r and a term of t years

Using the given values, we can solve for r.

10280 = 8000(1 +6r)

1.285 = 1 +6r . . . . . . . . divide by 8000

0.285 = 6r . . . . . . . . . . subtract 1

0.285/6 = r = 0.0475 = 4.75% . . . . . . divide by 6; express as %

Theo paid interest at the rate of 4.75%.

8 0

3 years ago

Oi can someone help meh plz

tekilochka [14]

Answer
1.5 and 12 i’m pretty sure
hope this helps and have a nice day :)

4 0

3 years ago

Read 2 more answers

Need answer ASAP!!!!

Brrunno [24]

Answer:

4

Step-by-step explanation:

The first triangle has the ratios 10:6:8. The next one has the ratios 5:3:x. If you have paid close attention, you can divide the first one by 2 to get the second one. 8/2 is 4 so the correct answer is 4.

Hope this helps plz mark brainliest if correct :D

5 0

3 years ago

The numbers 2-12 are written on cards and placed in the bag.what is the probability of picking an even number then replacing it

weeeeeb [17]

2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12

There are 11 numbers on cards.

6 cards contain even numbers.

Answer: p(even) = 6/11

There is only one card with a 7. After the first card is picked and returned, there are 11 cards in the bag again.

p(even then 7) = p(even) * p(7) = 6/11 * 1/11 = 6/121

Answer: p(even then 7) = 6/121

4 0

4 years ago

Two cars are driving towards an intersection from perpendicular directions.

FrozenT [24]

For a better understanding of the solution provided here please find the diagram in the attached file.

In the diagram, A is the intersection. B is the position of the first car and C is the position of the second car. As can be clearly seen, as per the directions given in the question, the cars and the intersection make a right triangle.

The distance between the first car and the intersection is $x$ and the distance between the second car and the intersection is $y$ . The distance between the two cars is depicted by $s$ . As we can see, $s$ is the hypotenuse of the right triangle. At the given instance the distances are 8 meters and 6 meters respectively. Thus, by the Pythagorean Theorem the hypotenuse will be:

$s=\sqrt{8^2+6^2}= \sqrt{100}=10$ ...............(Equation 1)

Now, we know that at any instant the Pythagorean Theorem holds and so we will have, in general:

$s^2=x^2+y^2$

Now, implicitly differentiating the above formula with respect to time, we get:

$2s\frac{ds}{dt}=2x \frac{dx}{dt}+2y \frac{dy}{dt}$

This can be further simplified by dividing both the sides by the common factor 2 as:

$s\frac{ds}{st}=x \frac{dx}{dy}+y\frac{dy}{dt}$ .................(Equation 2)

As we can see from the questions and the diagram, $\frac{dx}{dt}=-2 m/s$ and $\frac{dy}{dt}=-9 m/s$ . The negative sign is there because the distances y and x are reducing as the cars approach the intersection.