2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12
There are 11 numbers on cards.
6 cards contain even numbers.
Answer: p(even) = 6/11
There is only one card with a 7. After the first card is picked and returned, there are 11 cards in the bag again.
p(even then 7) = p(even) * p(7) = 6/11 * 1/11 = 6/121
Answer: p(even then 7) = 6/121
Answer:
8
Step-by-step explanation:
y = 2
z = 8
8y - z
= 8 ( 2 ) - 8
= 16 - 8
= 8
Answer: 1, 7, 1, 7, 1.
The given function : and f(1) = 1 for n ≥ 1
We put value of n=1,2,3,4 , we get
For n=1 ,
For n=2 ,
For n=3 ,
For n=4 ,
Hence, the first five terms of the given sequence are 1, 7, 1, 7, 1.
i think i am not sure
i am soo sorry if i gave it wrong but i think its A