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andreyandreev [35.5K]
3 years ago
8

What is the answer to this problem 6(1-5m)

Mathematics
1 answer:
Ivahew [28]3 years ago
5 0
Apply the distributive property.<span>6⋅1+6<span>(−5m<span>)

</span></span></span>Multiply <span>66</span> by <span>11</span> to get <span>66</span>.<span><span>6+6<span>(−5m)</span></span><span>6+6<span>(-5m)</span></span></span>Multiply <span><span>−5</span><span>-5</span></span> by <span>66</span> to get <span><span>−30</span><span>-30</span></span>.<span><span>6−30m</span><span>6-30m</span></span>Reorder <span>66</span> and <span><span>−30m</span><span>-30m</span></span>.<span>−30m+<span>6
So your answer is </span></span>−30m+6
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93/5 turned into a decimal is 18.6
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Solve x2 - 10x = -21
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Josie used 1/2 of the milk for pancakes this morning. If her brother and sister divided what was left to eat cookies with their
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Answer:

1/4 cup of milk

Step-by-step explanation:

= 1/2 ÷ 2

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4 0
2 years ago
Un cliente de un supermercado ha pagado un total de 240 por 16 litros de leche,4kg de hamon serrano y 8 litros de aceite de oliv
Vaselesa [24]

Answer:

1 litro de leche cuesta 2.5

1 kg de jamón serrano cuesta 35

1 litro de aceite de oliva cuesta 7,5

Step-by-step explanation:

Pregunta correcta completa

Un cliente de un supermercado ha pagado un total de 240 por 16 litros de leche,4kg de hamon serrano y 8 litros de aceite de oliva. Sabiendo que 1 litro de aceite cuesta el tripe de 1 litro de leche; que 1kg de jamon cuesta igual que el cliente tendria que pagar si hubiera comprado 5 litros de leche y 3 litros de aceite de oliva. Calcule el precio de cada artículo.

Solución

Deje que el precio de un litro de leche, un kilogramo de jamón serrano y un litro de aceite de oliva sea x, y y z respectivamente.

16 litros de leche, 4 kg de hamon serrano y 8 litros de aceite de oliva cuestan 240

16x + 4y + 8z = 240 (ecuación 1)

1 litro de aceite cuesta el triple de 1 litro de leche

z = 3x (ecuación 2)

Y ese 1 kg de jamón cuesta lo mismo que el cliente tendría que pagar si hubiera comprado 5 litros de leche y 3 litros de aceite de oliva.

y = 5x + 3z (ecuación 3)

Sustituyendo las ecuaciones 2 y 3 en la ecuación 1

16x + 4(5x + 3z) + 8(3x) = 240

16x + 20x + 12z + 24x = 240

Recordemos que z = 3x

36x + 12(3x) + 24x = 240

36x + 36x + 24x = 240

96x = 240

x = (240/96) = 2.5

z = 3x = 3 × 2.5 = 7.5

y = 5x + 3z = (5×2.5) + (3×7.5) = 35

English Translation

A supermarket customer has paid a total of 240 for 16 liters of milk, 4kg of hamon serrano and 8 liters of olive oil. Knowing that 1 liter of oil costs the tripe of 1 liter of milk; t that 1kg of ham costs the same as the customer would have to pay if he had bought 5 liters of milk and 3 liters of olive oil. Calculate the price of each item.

Solution

Let the price of a liter of milk, a kilogram of Serrano ham and a liter of olive oil be x, y and z respectively.

16 liters of milk, 4kg of hamon serrano and 8 liters of olive oil cost 240

16x + 4y + 8z = 240 (eqn 1)

1 liter of oil costs the triple of 1 liter of milk

z = 3x (eqn 2)

And that 1kg of ham costs the same as the customer would have to pay if he had bought 5 liters of milk and 3 liters of olive oil

y = 5x + 3z (eqn 3)

Substituting eqn 2 and 3 into eqn 1

16x + 4(5x + 3z) + 8(3x) = 240

16x + 20x + 12z + 24x = 240

Recall that z = 3x

36x + 12(3x) + 24x = 240

36x + 36x + 24x = 240

96x = 240

x = (240/96) = 2.5

z = 3x = 3 × 2.5 = 7.5

y = 5x + 3z = (5×2.5) + (3×7.5) = 35

1 liter of milk costs 2.5

1 kg of Serrano ham costs 35

1 liter of olive oil costs 7.5

Hope this Helps!!!

4 0
3 years ago
LaDanian wants to write the fraction 4 / 6 as a sum of unit fractions. what expression should he write
julsineya [31]
He <span>wants to write the fraction 4 / 6 as a sum of unit fractions. It is written as follows:
</span>
1/6 +1/6 +1/6+ 1/6= 4/6.

A unit fraction has a numerator of 1 so since 4 is the numerator in 4/6 you would have to add 1/6 for four times. 

Hope this answers the question. Have a nice day.
7 0
3 years ago
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