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kkurt [141]
3 years ago
6

A golf team's 666 members had the scores below in their most recent tournament:

Mathematics
1 answer:
stealth61 [152]3 years ago
7 0
Here is a scenario:

Mark recorded the following bowling scores for his last 9 games:


110, 92, 86, 203, 74, 105, 97, 112, 99

What was his mean score?

What was his median score?

Which of these better represents his bowling score for the last nine games?
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Help help help help please guys
maria [59]
I think the answer is 9
It's a smaller version of the other figure.
21/3=7
27/3=9
3 0
3 years ago
Simplify. Your answer should only contain only positive exponents.
Xelga [282]

Answer:

A

Step-by-step explanation:

6 0
2 years ago
Read 2 more answers
Im so lost, please help me asap
almond37 [142]

Answer:

it's so simple ....

x + 141 = 135

x = 135 - 141

x = -6

it means ur answer is a

8 0
2 years ago
Suppose the length of a side of<br> a square is s. Write a formula to find the<br> area of a square.
densk [106]

Answer:

A=sw

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
State the equation of the line<br> that is perpendicular to 4x-3y=10<br> through the point (-2,4)
Lynna [10]

The equation of the line  that is perpendicular to 4x - 3y = 10  through the point (-2,4) is y-4=\frac{-3}{4}(x+2)

<u>Solution:</u>

Given, line equation is 4x – 3y = 10  

We have to find a line that is perpendicular to 4x – 3y = 10 and passing through (-2, 4)

Now, let us find the slope of the given line,  

\text { Slope of a line }=\frac{-\mathrm{x} \text { coefficient }}{\mathrm{y} \text { coefficient }}=\frac{-4}{-3}=\frac{4}{3}

We know that, slope of a line \times slope of perpendicular line = -1

\begin{array}{l}{\text { Then, } \frac{4}{3} \times \text { slope of perpendicular line }=-1} \\\\ {\rightarrow \text { slope of perpendicular line }=-1 \times \frac{3}{4}=-\frac{3}{4}}\end{array}

Now, slope of our required line = \frac{-3}{4} and it passes through (-2, 4)

<em><u>The point slope form is given as:</u></em>

\begin{array}{l}{y-y_{1}=m\left(x-x_{1}\right) \text { where } m \text { is slope and }\left(x_{1}, y_{1}\right) \text { is point on the line. }} \\\\ {\text { Here in our problem, } m=-\frac{3}{4}, \text { and }\left(x_{1}, y_{1}\right)=(-2,4)} \\\\ {\text { Then, line equation } \rightarrow y-4=-\frac{3}{4}(x-(-2))}\end{array}

y-4=\frac{-3}{4}(x+2)

Hence the equation of line is found out

6 0
2 years ago
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