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My name is Ann [436]
3 years ago
11

(10×2+99×-5)÷(×+10)=

Mathematics
1 answer:
allochka39001 [22]3 years ago
5 0

The answer to (10 x 2+99 x -5) / (x+10) is 11.4

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In the figure, a∥b and m∠3 = 34°.<br><br> What is the m∠7 ?<br><br> Enter your answer in the box.
solmaris [256]

Answer:

∠7 = 34°

Step-by-step explanation:

Since a and b are parallel lines then

∠3 and ∠7 are corresponding angles and congruent, so

∠7 = ∠3 = 34°

4 0
3 years ago
brian bought X apples and some oranges. Brian bought 3 more oranges than apples. find the toal number of fruit brian bought in t
Sophie [7]


<span>We can make an equation through that information.
X+3+3
</span>Brian bought 3 more of the oranges and apples, and that will get you
X+3+3
=
X+6
 
8 0
3 years ago
The Center for Medicare and Medical Services reported that there were 295,000 appeals for hospitalization and other Part A Medic
Ymorist [56]

Answer:

(a) 0.00605

(b) 0.0403

(c) 0.9536

(d) 0.98809

Step-by-step explanation:

We are given that 40% of first-round appeals were successful (The Wall Street Journal, October 22, 2012) and suppose ten first-round appeals have just been received by a Medicare appeals office.

This situation can be represented through Binomial distribution as;

P(X=r)= \binom{n}{r}p^{r}(1-p)^{n-r} ; x = 0,1,2,3,....

where,  n = number of trials (samples) taken = 10

            r = number of success

            p = probability of success which in our question is % of first-round

                   appeals that were successful, i.e.; 40%

So, here X ~ Binom(n=10,p=0.40)

(a) Probability that none of the appeals will be successful = P(X = 0)

     P(X = 0) = \binom{10}{0}0.40^{0}(1-0.40)^{10-0}

                   = 1*0.6^{10} = 0.00605

(b) Probability that exactly one of the appeals will be successful = P(X = 1)

     P(X = 1) = \binom{10}{1}0.40^{1}(1-0.40)^{10-1}

                  = 10*0.4^{1} *0.6^{10-1} = 0.0403

(c) Probability that at least two of the appeals will be successful = P(X>=2)

    P(X >= 2) = 1 - P(X = 0) - P(X = 1)

                     = 1 - \binom{10}{0}0.40^{0}(1-0.40)^{10-0} - \binom{10}{1}0.40^{1}(1-0.40)^{10-1}

                     = 1 - 0.00605 - 0.0403 = 0.9536

(d) Probability that more than half of the appeals will be successful =             P(X > 0.5)

  For this probability we will convert our distribution into normal such that;

   X ~ N(\mu = n*p=4,\sigma^{2}= n*p*q = 2.4)

  and standard normal z has distribution as;

      Z = \frac{X-\mu}{\sigma} ~ N(0,1)

  P(X > 0.5) = P( \frac{X-\mu}{\sigma} > \frac{0.5-4}{\sqrt{2.4} } ) = P(Z > -2.26) = P(Z < 2.26) = 0.98809

3 0
3 years ago
PLEEEEESSSSE HELP ON THIS QUESTION, I WILL MARK FOR BRAINLIEST!!!!!!
Ivanshal [37]
A: linear term= how many books printed. Constant= initial 1700 books to start

B: R(y) = 7.50y - C(x)
6 0
3 years ago
the following data values represent a population. what is the variance of the values? 17, 5, 11, 1, 11
Vladimir [108]
Variance = summation of (x - mean)^2 all divided by the number of dataset.
mean = (17 + 5 + 11 + 1 + 11)/5 = 9

Variance = [(17 - 9)^2 + (5 - 9)^2 + (11 - 9)^2 + (1 - 9)^2 + (11 - 9)^2]/5 = (8^2 + (-4)^2 + 2^2 + (-8)^2 + 2^2}/5 = (64 + 16 + 4 + 64 + 4)/5 = 152/5 = 30.4
4 0
2 years ago
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