-6, -7, -8 degrees Celsius. I know these temperatures are colder because they are are a higher negative, and when measuring temperature the higher the negative the colder the temperature is.
Hopes that’s what you are looking for!
The solution is 2sqrt77/77. You just fill in 2/3 for the x's. When you do that, you do that you get (2/3)/sqrt(9-[2/3]^2) which, simplified, is (2/3)/sqrt(9-[4/9]). Now use the common denominator under the radical of 9 to get (2/3)/sqrt([81-4]\9). Simplifying even further gives you (2/3)/([sqrt(77)]/3). Now do that division by multiplying 2/3 by the reciprocal of ([sqrt(77)]/3) to get 2/sqrt77. I rationalized the denominator to get that result up there.
11,850 x .9 = 11,605
11605 x . 9 = 9,598.5 year 2
9,598.5 x .9 = 8,638.65
8,635 x .9 = 7,774.785 year 4
7,774.785 x .9 = 6,997.31
6,6997.31 x .9 = 6297.58 year 6
6297.58 x .9 = 5,667.82
5,667.82 x .9 = 5,101.04 year 8
The answer is D
I don’t know what your trying to find but you basically create an equation, like this
3x+5x=80
and solve which would result in x=10
so there is
30 geckos
and
50 anole lizards
