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HACTEHA [7]
3 years ago
9

What is 8÷3 rounded to the nearest 10th

Mathematics
1 answer:
Volgvan3 years ago
6 0
8÷3 is 2.666666667, 6 is greater than 5 so rounded to the nearest tenth it is 2.7
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2|3x - 2|= 14 how would you solve this absolute value equation?
Feliz [49]

Answer: 2. |3x-2|= 14

|3x-2|=2.7/2

|3x-2|=7

x∈ {3,-5/3

Step-by-step explanation: \frac{5}{3}

6 0
3 years ago
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How many boys are in a class of thirty-five student if the girls outnumber boys by five
Diano4ka-milaya [45]
15 Boys because 35-5 is 30 then divide 30 by 2 to get 15
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3 years ago
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Identify the lower class​ limits, upper class​ limits, class​ width, class​ midpoints, and class boundaries for the given freque
maw [93]

Answer:

The number of individuals included in the summary is 146.

Step-by-step explanation:

The frequency distribution table provided is as follows:

Class Intervals    Frequency

    100 - 199               24

   200 - 299              90

   300 - 399              27

   400 - 499                1

   500 - 599               4

The lower class limit it the smallest value of each class interval.

Lower class limit = {100, 200, 300, 400, 500}

The upper class limit it the highest value of each class interval.

Upper class limit = {199, 299, 399, 499, 599}

The lower class boundaries are the lower class limits decreased by 0.5 and the upper class boundaries are the upper class limits increased by 0.5.

Class boundaries:

   99.5 - 199.5  

  199.5 - 299.5

  299.5 - 399.5

  399.5 - 499.5

  499.5 - 599.5

The class width is the difference between the class boundaries of each class.

Class width = 199.5 - 99.5 = 100

So, the class width is 100.

The midpoints of a class is the average value of the boundaries of a class.

\text{Midpoint}_{100-199}=\frac{\text{Lower class boundary} + \text{Upper class boundary}}{2}\\

                         =\frac{99.5+199.5}{2}\\\\=149.5

\text{Midpoint}_{200-299}=\frac{\text{Lower class boundary} + \text{Upper class boundary}}{2}\\

                         =\frac{199.5+299.5}{2}\\\\=249.5

\text{Midpoint}_{300-399}=\frac{\text{Lower class boundary} + \text{Upper class boundary}}{2}\\

                         =\frac{299.5+399.5}{2}\\\\=349.5

\text{Midpoint}_{400-499}=\frac{\text{Lower class boundary} + \text{Upper class boundary}}{2}\\

                         =\frac{399.5+499.5}{2}\\\\=449.5

\text{Midpoint}_{500-599}=\frac{\text{Lower class boundary} + \text{Upper class boundary}}{2}\\

                         =\frac{499.5+599.5}{2}\\\\=549.5

The number of individuals included in the summary is the sum of all frequencies.

\text{Number of Individuals}=24 + 90 + 27 + 1 + 4=146

Thus, the number of individuals included in the summary is 146.

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2 years ago
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What's the nearest integer and the nearest tenth
natali 33 [55]

Answer:

nearest integer 27 by 4

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3 years ago
Lane's arm span is 61 inches. If his height is 1⁄4 foot longer than his arm span, how tall is he? feet and inches
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If lane's are span is 61 inches. his height is 1/4 foot long than his arm span. his height is <span>5 ft 3 inches </span> 
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