Answer:
class boundaries are the end points of an open interval which contains the class interval such that the lower class boundary (LCB) is the LCL minus one-half the tolerance and the upper class boundary (UCB) is the UCL plus one -half the tolerance.
Answer:
<em>$7,196.42 </em>
Step-by-step explanation:
Using the compound interest formula to fins the amount after 10years;
A = P(1+r)^n
Principal P = $400,000
Rate r = 8% = 0.08
Time t = 10 years
Substitute
A = 400,000(1+0.08)^10
A = 400,000(1.08)^10
A = 400,000(2.1589)
A = 863,569.99
A ≈ 863,570
Hence the amount after 10 years is $863,570
Monthly deposit = $863,570/120 (10 years is equivalent to 120months)
Monthly deposit = 7,196.42
<em>Therefore he will have to deposit $7,196.42 into his account monthly</em>
Answer:
Option D is correct
Step-by-step explanation:
Using the given diagram, we want to know the equation that is true
Option A is wrong as both are on a straight line and in fact should add up to equal 180 and not be equal to each other
Option B is not correct as both are supplementary and does not equal each other
Option C is not correct, both are corresponding to each other and should not add up to 90
Option D is correct
Both angles are supplementary as they are exterior angles that add up to 180
<h3>
Answer: 360</h3>
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Explanation:
We have 3 even values (2,4, and 6) so this is the number of choices we have for the units digit. Recall that a number is even if the units digit is 0,2,4,6 or 8.
Once we have the units digit selected, we have 6-1 = 5 choices for the first slot, 6-2 = 4 choices for the second slot, and so on until we get down to 6-5 = 1 choice for the fifth slot
We could write it out like this
- slot one = 5 choices
- slot two = 4 choices
- slot three = 3 choices
- slot four = 2 choices
- slot five = 1 choice
- slot six = units digit = 3 choices
Multiply those values out: 5*4*3*2*1*3 = 360
There are 360 different even numbers possible.
Answer:
4/663
Step-by-step explanation:
Probability is the likelihood or chance that an event will occur.
Probability = Expected outcome/Total outcome
Since we are to draw from a pack of card, the total outcome will be 52
Since there are 4 hearts;
Pr(selecting heart) = 4/52 = 1/13
If a club is then selected without replacement, the total number of card remaining will be 51;
Pr(selecting a heart) = 4/51
probability of drawing a heart and a club in that order = 4/52 * 4/51
probability of drawing a heart and a club in that order = 16/2652
probability of drawing a heart and a club in that order = 4/663
