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3 years ago

13

Got a fairly simple looking system of equations, 2k+4y=20, and 3x+6y=30 Don't understand how to prove what values of k provide -

1 solution - no solutions - and many solutions

1 answer:

Leya [2.2K]3 years ago

6 0

Answer:

2kx+4y=20 ⇒ kx+2y=10

3x+6y=30 ⇒ x+2y= 10

k is the coefficient of x, so it is the slope of the line

when k=1, both equations will be same, then there are many solutions
when k=0 there is one solution
when k is anything different, then the lines will be parallel, so no solutions

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