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Furkat [3]
3 years ago
13

Got a fairly simple looking system of equations, 2k+4y=20, and 3x+6y=30 Don't understand how to prove what values of k provide -

1 solution - no solutions - and many solutions
Mathematics
1 answer:
Leya [2.2K]3 years ago
6 0

Answer:

2kx+4y=20 ⇒ kx+2y=10

3x+6y=30 ⇒ x+2y= 10

k is the coefficient of x, so it is the slope of the line

  • when k=1, both equations will be same, then there are many solutions
  • when k=0 there is one solution
  • when k is anything different, then the lines will be parallel, so no solutions
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Please help I'll give the brainiest to the right answer!
Anna [14]

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x=1

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Because vertical angles are always equal, we want to solve 50x+10=70x-10.

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Look at pic down underrr
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Answer:

Triangle rsu = Triangle tus

Statements Reasons

UR ≅ TS  Definition of Rectangle

US ≅ US Reflexive Property

<U, <T, <R, <S are all congruent and right angles

Definition of Rectangle

ΔRSU ≅ ΔTUS Side, Angle, Side

UR ≅ TS     CPCTC

Just draw a reverse angle,hence you get comparison.

So, satisfying S-S-S

RUS  ≅ SUT

RSU ≅ TUS

So, angle

URS = angle TUS

2. Pythagoras Theorem

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Triangle TUS

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