The given points are
P = (-4,11)
Q = (-5,8)
The x-component of vector QP is
-4 - (-5) = 1
The y-component of vector QP is
11 - 8 = 3
The vector QP is
(1,3) or

The magnitude of the vector is
√(1² + 3²) = √(10)
Answer:

The magnitude is √(10).
Problem 1
Draw a straight line and plot P anywhere on it. Use the compass to trace out a faint circle of radius 8 cm with center P. This circle crosses the previous line at point Q.
Repeat these steps to set up another circle centered at Q and keep the radius the same. The two circles cross at two locations. Let's mark one of those locations point X. From here, we could connect points X, P, Q to form an equilateral triangle. However, we only want the 60 degree angle from it.
With P as the center, draw another circle with radius 7.5 cm. This circle will cross the ray PX at location R.
Refer to the diagram below.
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Problem 2
I'm not sure why your teacher wants you to use a compass and straightedge to construct an 80 degree angle. Such a task is not possible. The proof is lengthy but look up the term "constructible angles" and you'll find that only angles of the form 3n are possible to make with compass/straight edge.
In other words, you can only do multiples of 3. Unfortunately 80 is not a multiple of 3. I used GeoGebra to create the image below, as well as problem 1.
48 divided 12 equal 4 ⇒ 4 times of 12 to go to 48
<h2>ANSWER:</h2><h2>49.2 </h2>
Based on your question Two forces of 19.8 pounds and 36.5 pounds act on a body with an angle of 61.4 degrees between them.
After setting up the vectors on the plane and doing the required math
The answer is 49.2 pounds
<h2 />
The slope formula is delta y/delta x=m
You can choose any two points. Let's choose (0,25) and (1,30)
30-25/1-0=5/1=5
Slope intercept form is y=mx+b
b=the y intercept
y=5x+25 since (0,25) is the coordinates for the y inthercept.
Plug in 200: y=5(200)+25
Simplify and you get that y=1025
Your answer is 1025
Your welcome