If x>4, then the quantity x-3 inside the absolute value symbol is already positive. So, in this case, |x-3| => x-3, and x-3 is all you need to write.
It’s not my answer but I think it’s correct!
Split the object then find the 2 areas then subtract
Angle BDC is given as 38° but not drawn in the figure. Amateurs.
We calculate angle DBC
DBC = 180° - 96° - 38° = 180° - 134°
We won't bother subtracting because we're really after
angle ABD = 180° - DBC = 134°
Now we have a Law of Cosines situation,
AD² = AB² + BD² - 2(AB)(BD) cos ABD
AD = √( 5.8² + 27.3² - 2(5.8)(27.3) cos 134°)
AD ≈ 31.61 m
Answer: 31.6 m
Answer:
0.6568 = 65.68% probability that she would be correct.
Step-by-step explanation:
When the distribution is normal, we use the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
45000, 45500, 44500, 46000 and 44000 units. This rate of sales is considered average for the product over the last twenty years or so.
This means that:

Standard deviation of 1500 units.
This means that 
What is the likelihood that she would be correct if she predicts sales between 43000 and 46000?
This is the pvalue of Z when X = 46000 subtracted by the pvalue of Z when X = 43000. So
X = 46000



has a pvalue of 0.7486
X = 43000



has a pvalue of 0.0918
0.7486 - 0.0918 = 0.6568
0.6568 = 65.68% probability that she would be correct.