Question

Find the vertical asymptote(s) of f (x) = StartFraction x squared minus 1 Over 2 x + 6 EndFraction.

Answer 1

Explanation:

We have the function:

$f(x)=\frac{x^2-1}{2x+6}$

The vertical asymptote can be found when the denominator equal zero, therefore:

$2x+6=0 \\ \\ 2x=-6 \\ \\ x=-3$

So the vertical asymptote occur at $x=-3$