What is the zeros of the quadratic function y=x^2+14x+24

1 answer:

6 0

Step-by-step explanation:

${x}^{2} + 14x + 24 = 0 \\ {x}^{2} + 12x + 2x + 24 = 0 \\ x(x + 12) + 2(x + 12) = 0 \\ (x + 12)(x + 2) = 0\\ x = - 12 \\ x = - 2$

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