Answer:
Player II should remove 14 coins from the heap of size 22.
Step-by-step explanation:
To properly answer this this question, we need to understand the principle and what it is exactly is being asked.
This question revolves round a game of Nim
What is a game of Nim: This is a strategic mathematical game whereby, two opposing sides or opponent take turns taking away objects from a load or piles. On each turn, a player remove at least an object and may remove any number of objects provided they all come from the same heap/pile.
Now, referring back to the question, we should first understand that:
22₂ = 1 0 1 1 0
19₂= 1 0 0 1 1
14₂= 0 1 1 1 0
11₂= 0 1 0 1 1
and also that the “bit sums” are all even, so this is a balanced game.
However, after Player I removes 6 coins from the heap of size 19, Player II should remove 14 coins from the heap of size 22.
Answer: D, 1/12
Explanation:
Since it says how much MORE, we subtract. SO
3/4 - 2/3= 1/12
Answer:
3 liters
Step-by-step explanation:
if 1.5 liters is 50% of the original amount, then to find the original amount you must multiply by two, or:
1.5 liters ×2=3 liters
I just worked it out and I got 6 3/28
Im sorry if that's wrong
