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2 years ago

Select all the equations

Mathematics

1 answer:

Harlamova29_29 [7]2 years ago

7 0

Answer:

is the correct answer

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Nadia is investigating rotations about the center of regular polygons that carry the regular polygon onto itself. She claims tha

GalinKa [24]

Answer:

$\theta_1 \ n\ \theta_2 = 120, 240$

Step-by-step explanation:

The question is incomplete, as the angles of rotation are not stated.

However, I will list the angles less than 360 degrees that will carry the hexagon and the nonagon onto itself

We have:

$Nonagon = 9\ sides$

$Hexagon = 6\ sides$

Divide 360 degrees by the number of sides in each angle, then find the multiples.

<u>Nonagon</u>

$\theta = \frac{360}{9} =40$

List the multiples of 40

$\theta_1 = 40, 80, 120, 160, 200, 240, 280, 320$

<u>Hexagon</u>

$\theta = \frac{360}{6} =60$

List the multiples of 60

$\theta_2 = 60, 120, 180, 240, 300$

List out the common angles

$\theta_1 = 40, 80, 120, 160, 200, 240, 280, 320$

$\theta_2 = 60, 120, 180, 240, 300$

$\theta_1 \ n\ \theta_2 = 120, 240$

This means that, only a rotation of $120, 240$ will lift both shapes onto themselves, when applied to both shapes.

The other angles will only work on one of the shapes, but not both at the same time.

7 0

3 years ago

Anyone Know This Answer ?

OverLord2011 [107]

I hope this helps you

M^2+R^2=W^2

M^2+16=25

M^2=9

7 0

3 years ago

Read 2 more answers

What is each power of i with its multiplicative inverse.

pentagon [3]

Answer:

1) multiplicative inverse of i = -i

2) Multiplicative inverse of i^2 = -1

3) Multiplicative inverse of i^3 = i

4) Multiplicative inverse of i^4 = 1

Step-by-step explanation:

We have to find multiplicative inverse of each of the following.

1) i

The multiplicative inverse is 1/i

if i is in the denominator we find their conjugate

$=1/i * i/i\\=i/i^2\\=We\,\, know\,\, that\,\, i^2 = -1\\=i/(-1)\\= -i$

So, multiplicative inverse of i = -i

2) i^2

The multiplicative inverse is 1/i^2

We know that i^2 = -1

1/-1 = -1

so, Multiplicative inverse of i^2 = -1

3) i^3

The multiplicative inverse is 1/i^3

We know that i^2 = -1

and i^3 = i.i^2

$1/i^3\\=1/i.i^2 \\=1/i(-1)\\=-1/i * i/i\\=-i/i^2\\= -i/-1\\= i$

so, Multiplicative inverse of i^3 = i

4) i^4

The multiplicative inverse is 1/i^4

We know that i^2 = -1

and i^4 = i^2.i^2

$=1/i^2.i^2\\=1/(-1)(-1)\\=1/1\\=1$

so, Multiplicative inverse of i^4 = 1

3 0

3 years ago

WILL MARK BRAINLIEST TO THE FIRST PERSON!!!!

xxTIMURxx [149]

Answer:

I think the answer is 105

7 0

3 years ago

A projectile was launched straight up from the ground with an initial velocity of 48 ft/s. The height of the projectile t second

alex41 [277]

Factor f(t) and you can identify the values of t for which the height is zero.
.. f(t) = -16t(t -3)

The projectile lands after 3 seconds in the air. (selection A)

8 0

3 years ago