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3 years ago

5c + 2a − b; a = 5, b = 11, and c = 3

2 answers:

8 0

5 times 3 = 15.
2 times 5 = 10
alright let's begin!
15 + 10 - 11
25 - 11 = 14
Hope this helped you!
please give brainliest.

horsena [70]3 years ago

8 0

5x3=15 + 2x5=10 - 11
15+10=25
25-11=14

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Evaluate lim x=π/4(3x - tanx)

Karo-lina-s [1.5K]

Answer:

$\lim_{x \to\frac{\pi }{4} } (3x-tanx)$ = $3(\frac{\pi }{4} )$

Step-by-step explanation:

Explanation:-

Given that

$\lim_{x \to\frac{\pi }{4} } (3x-tanx)$

= $\lim_{x \to\frac{\pi }{4} } (3x) - \lim_{x \to\frac{\pi }{4} } tanx)$

= $3(\frac{\pi }{4} )+tan(\frac{\pi }{4} )$

= $3(\frac{\pi }{4} )+ 1 )$

= $3(\frac{\pi }{4} )$

5 0

3 years ago

Can some one plz Solve this. 5 - 2x < 7.

kow [346]

Answer:

x > 1

Step-by-step explanation:

5 - 2x < 7

-5 - 5

-2x < 2

/-2 /-2

(dividing by negative switches the sign)

x >- 1

5 0

3 years ago

Read 2 more answers

What is the answer to this ? PLEASE HELP I HAVE 3 minutes

inn [45]

Answer:

(2, 4)

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Equality Properties

Multiplication Property of Equality
Division Property of Equality
Addition Property of Equality
Subtract Property of Equality

Algebra I

Solving systems of equations using substitution/elimination

Step-by-step explanation:

Step 1: Define Systems

y = 2x

x = -y + 6

Step 2: Solve for y

Substitution

Substitute in x: y = 2(-y + 6)
Distribute 2: y = -2y + 12
Isolate y terms: 3y = 12
Isolate y: y = 4

Step 3: Solve for x

Define equation: x = -y + 6
Substitute in y: x = -4 + 6
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3 0

3 years ago

don walked 3 3/5 miles on Friday, 3.7 miles on saturday, and 3 5/8 miles on sunday. list the distances from least to greatest

astraxan [27]

Solution:

we are given that

Don walked 3 3/5 miles on Friday

It can be re-written as

$3\frac{3}{5}miles=\frac{18}{5}= 3.6$ miles

3 5/8 miles on sunday.

It can be re-written as

$3\frac{5}{8}miles=\frac{29}{8}= 3.625$ miles

an d He walk 3.7 miles on satarday.

The distances from least to greatest is 3.6, 3.625, 3.7

The distances from least to greatest is $3\frac{3}{5}$ miles, $3\frac{5}{8}$ miles, 3.7 miles.

8 0

3 years ago

One more time!

CaHeK987 [17]

Since q(x) is inside p(x), find the x-value that results in q(x) = 1/4

$\frac{1}{4} = 5 - x^2\ \Rightarrow\ x^2 = 5 - \frac{1}{4}\ \Rightarrow\ x^2 = \frac{19}{4}\ \Rightarrow \\
x = \frac{\sqrt{19} }{2}$

so we conclude that
$q(\frac{\sqrt{19} }{2} ) = 1/4$

therefore

$p(1/4) = p\left( q\left(\frac{ \sqrt{19} }{2} \right) \right)$

plug $x=\sqrt{19}/2$ into p( q(x) ) to get answer

$p(1/4) = p\left( q\left( \frac{ \sqrt{19} }{2} \right) \right)\ \Rightarrow\ \dfrac{4 - \left( \frac{\sqrt{19} }{2}\right)^2 }{ \left( \frac{\sqrt{19} }{2}\right)^3 } \Rightarrow \\ \\ \dfrac{4 - \frac{19}{4} }{ \frac{19\sqrt{19} }{8}} \Rightarrow \dfrac{8\left(4 - \frac{19}{4}\right) }{ 8 \cdot \frac{19\sqrt{19} }{8}} \Rightarrow \dfrac{32 - 38}{19\sqrt{19}} \Rightarrow \dfrac{-6}{19\sqrt{19}} \cdot \frac{\sqrt{19}}{\sqrt{19}}\Rightarrow$

$\dfrac{-6\sqrt{19} }{19 \cdot 19} \\ \\ \Rightarrow -\dfrac{6\sqrt{19} }{361}$

$p(1/4) = -\dfrac{6\sqrt{19} }{361}$

3 0

3 years ago