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professor190 [17]
3 years ago
8

What's a coordinate rule

Mathematics
1 answer:
Sav [38]3 years ago
5 0
A coordinate rule is like were the the shape is I think 
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The perimeter of the figure below is 133.1 ft. Find the length of the missing side.
Fantom [35]

Answer:

9.6 ft

Step-by-step explanation:

133.1 - (9.7 + 8.9 + 8.9 + 8.9 + 18.6 + 11.6 + 20.5 + 27.5 + 8.9)

133.1 - 123.5

= 9.6

3 0
3 years ago
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What is 207/500 simplified
bezimeni [28]
207/500 is already in simplest form
8 0
4 years ago
Bonjour je suis en 3 ème pouvez vous m'aider s'il vous plaît une voiture met 2 h 30 pour faire 200 km 1. Calculer sa vitesse moy
Lemur [1.5K]

Répondre:

Explication étape par étape:

Vitesse = Distance / Temps

Distance donnée = 200 km

Durée = 2 h 30

Convertir le temps en heures

Depuis 60 minutes = 1h

2 heures 30 minutes = 2+ (30/60)

2h30 = 2 + 1/2 hors

2 heures 30 minutes = 2,5 heures

Vitesse en km / h = 200 km / 2,5 h

Vitesse en km / h = 80 km / h

D'où sa vitesse moyenne en km / h est de 80 km / h

a) Distance = Vitesse * Temps

Vitesse donnée = 80 km / h

Durée = 3h15

Temps = 3 15/60 h

Durée = 3,25 h

Distance = 80 * 3,25

Distance parcourue en 3h15 = 260 km

b) Distance = Vitesse * Temps

Vitesse donnée = 80 km / h

Durée = 42 minutes

Durée = 42/60 h

Distance = 80 * 42/60

Distance = 3360/60

Distance = 56 km

Distance parcourue en 42 minutes = 56 km

c) Distance = Vitesse * Temps

Vitesse donnée = 80 km / h

Durée = 3 h 36 minutes

Temps = 3 36/60 h

Durée = 3,6 h

Distance = 80 * 3,6

Distance = 288 km

Distance parcourue en 3 h 36 min = 288 km

d) Distance donnée = 540 km

Vitesse = 80 km / h

Temps = Distance / Vitesse

Heure = 540/80

Temps = 6,75 heures

Par conséquent, le temps nécessaire pour parcourir 540 km est de 6,75 heures

7 0
3 years ago
PLSS HELPPP<br><br> FIRST PERSON TO ANSWER GETS BRAINLIEST!!!
notka56 [123]
Answer: 38, 76, 65

explanation: i’m good at math
6 0
3 years ago
Read 2 more answers
How many different committees can be formed from 10 teachers and 37 students of the committee consist of three teachers and two
pashok25 [27]

Answer:

<em>79,920 different ways</em>

Step-by-step explanation:

Combination has to do with selection:

If we are to select 3 teachers from a pool of 10 teachers to form a committee, this can be done in 10C3 number of ways.

10C3 = 10!/(10-3)!3!

10C3 = 10!/7!3!

10C3 = 10*9*8*7!/7!3!

10C3 = 10*9*8/3*2

10C3 = 720/6

10C3 = 120 ways

Similarly, selecting five 2 students from a pool of 37 students to form a committee, this can be done in 37C2 difference ways;

37C2 = 37!/(37-2)!2!

37C2 = 37!/35!2!

37C2 = 37*36*35!/35!*2

37C2 = 37*36/2

37C2 = 37 * 18

37C2 = 666 ways

<em>Hence the total number of ways that the 5 committees can be selected is expressed as 10C3 * 37C3 = 120 * 666</em>

<em> 120 * 666 = 79,920 ways</em>

3 0
3 years ago
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