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3 years ago

Choose one of the factors of x^15 − 64.

1 answer:

6 0

x^15 − 64
= x^15 - 4^3
=(x^5)^5 - 4^3
= (x^5 - 4) (x^10 + 4x^5 + 16)

answer
a. x^5 − 4

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Evaluate O! + 1!. a. 1 b. 2

ss7ja [257]

Answer:

0! = 1

1! = 1

0! + 1! = 1 + 1 = 2

4 0

3 years ago

Finding area of shaded sectors.

tekilochka [14]

Answer:

69.81 sq. m. (rounded to 2 decimal places)

Step-by-step explanation:

The sector of a circle is "part" or "portion" of a circle. The formula for the area of a sector is:

$A=\frac{\theta}{360}*\pi r^2$

Where

$\theta$ is the central angle

r is the radius

Given the figure, the arc is given as 80 degrees, but not the central angle of the shaded sector. But from geometry we know that the central angle and the intercepted arc have the same measure. So we can say:

$\theta = 80$

Also, the radius of the circle shown is 10 meters, so

r = 10

Now, we substitute in formula and find our answer:

$A=\frac{\theta}{360}*\pi r^2\\A=\frac{80}{360}*\pi (10)^2\\A=\frac{2}{9}*100\pi\\A=\frac{200\pi}{9}\\A=69.81$

Thus,

The area of the shaded sector is 69.81 sq. meters.

5 0

2 years ago

An automobile company wants to determine the average amount of time it takes a machine to assemble a car. A sample of 40 times y

aksik [14]

Answer:

A 98% confidence interval for the mean assembly time is [21.34, 26.49] .

Step-by-step explanation:

We are given that a sample of 40 times yielded an average time of 23.92 minutes, with a sample standard deviation of 6.72 minutes.

Firstly, the pivotal quantity for finding the confidence interval for the population mean is given by;

P.Q. = $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample average time = 23.92 minutes

s = sample standard deviation = 6.72 minutes

n = sample of times = 40

$\mu$ = population mean assembly time

Here for constructing a 98% confidence interval we have used a One-sample t-test statistics because we don't know about population standard deviation.

So, a 98% confidence interval for the population mean, $\mu$ is;

P(-2.426 < $t_3_9$ < 2.426) = 0.98 {As the critical value of z at 1% level

of significance are -2.426 & 2.426}

P(-2.426 < $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ < 2.426) = 0.98

P( $-2.426 \times {\frac{s}{\sqrt{n} } }$ < ${\bar X-\mu}$ < $2.426 \times {\frac{s}{\sqrt{n} } }$ ) = 0.98

P( $\bar X-2.426 \times {\frac{s}{\sqrt{n} } }$ < $\mu$ < $\bar X+2.426 \times {\frac{s}{\sqrt{n} } }$ ) = 0.98

98% confidence interval for $\mu$ = [ $\bar X-2.426 \times {\frac{s}{\sqrt{n} } }$ , $\bar X+2.426 \times {\frac{s}{\sqrt{n} } }$ ]

= [ $23.92-2.426 \times {\frac{6.72}{\sqrt{40} } }$ , $23.92+2.426 \times {\frac{6.72}{\sqrt{40} } }$ ]

= [21.34, 26.49]

Therefore, a 98% confidence interval for the mean assembly time is [21.34, 26.49] .

7 0

2 years ago

How do you find the equation of a scatter plot?

Mashcka [7]

Make a line of best fit then find the slope and y intercept. put it into the y=mx + b form.

m=slope
b=y intercept

3 0

3 years ago

Which of the following shows a relationship of 4,000 as ten times greater than 400?

stira [4]

400 times ten because when you multiply you get 40,000.

8 0

2 years ago