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Irina-Kira [14]
3 years ago
13

Choose one of the factors of x^15 − 64.

Mathematics
1 answer:
lara [203]3 years ago
6 0
<span>x^15 − 64
</span><span>= x^15 - 4^3
=(x^5)^5 - 4^3
= (x^5 - 4) (x^10 + 4x^5 + 16)

answer
</span><span>a. x^5 − 4</span>
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solve the equations below. make sure you say how many solutions each equation has(MCC.8.EE.7a) A. 5p-9=7p-19 b. 5p-9= 5p-19 C. 5
Sedaia [141]
<h3>Answer:</h3>
  • A) p = 5, one solution
  • B) no solutions
  • C) infinite solutions
<h3>Step-by-step explanation:</h3>

A) Add 19-5p to each side of the equation:

... 10 = 2p

... 5 = p . . . . . divide by the coefficient of p

B) Subtract 5p from both sides of the equation:

... -9 = -19 . . . . . there is <em>no value of p</em> that will make this true. (No solution.)

C) Subtract 5p from both sides of the equation:

... -9 = -9 . . . . . this is true for <em>every value of p</em>. (Infinite solutions.)

6 0
3 years ago
For the polynomial function ƒ(x) = −x6 + 3x4 + 4x2, find the zeros. Then determine the multiplicity at each zero and state wheth
murzikaleks [220]

There is a multiple zero at 0 (which means that it touches there), and there are single zeros at -2 and 2 (which means that they cross). There is also 2 imaginary zeros at i and -i.


You can find this by factoring. Start by pulling out the greatest common factor, which in this case is -x^2.


-x^6 + 3x^4 + 4x^2

-x^2(x^4 - 3x^2 - 4)


Now we can factor the inside of the parenthesis. You do this by finding factors of the last number that add up to the middle number.


-x^2(x^4 - 3x^2 - 4)

-x^2(x^2 - 4)(x^2 + 1)


Now we can use the factors of two perfect squares rule to factor the middle parenthesis.


-x^2(x^2 - 4)(x^2 + 1)

-x^2(x - 2)(x + 2)(x^2 + 1)


We would also want to split the term in the front.


-x^2(x - 2)(x + 2)(x^2 + 1)

(x)(-x)(x - 2)(x + 2)(x^2 + 1)


Now we would set each portion equal to 0 and solve.


First root

x = 0 ---> no work needed


Second root

-x = 0 ---> divide by -1

x = 0


Third root

x - 2 = 0

x = 2


Forth root

x + 2 = 0

x = -2


Fifth and Sixth roots

x^2 + 1 = 0

x^2 = -1

x = +/- \sqrt{-1}

x = +/- i

7 0
3 years ago
Write 81.9 as a mixed number.
Digiron [165]

Answer:

81 9/10

Step-by-step explanation:

6 0
3 years ago
The sequence an = 8, 13, 18, 23, ... is the same as the sequence a1 = 8, an = an-1 + 5.
harkovskaia [24]
Actually, this answer would be true. Why?

 The first equation is: a(sub <em>n</em>) = 8, 13, 18, 23

The second is: a(sub 1)=8 ; a(sub <em>n</em>)= a(sub <em>n</em>-1)+5
if you wish to find the second term, plug two into the equation for <em /><em>n</em> 
8+5=13
to find the third, plug the second term, 13, in for <em>n.</em> 
13+5=18.

Hope this helped! I know it's a bit on the late side, but at least you can get the general idea!
8 0
3 years ago
Read 2 more answers
Expand the given power using the Binomial Theorem. (z – 11)4
nekit [7.7K]

Answer:

(z-11)^{4}=z^{4}-44z^{3}+726z^{2}-5324z+14641

Step-by-step explanation:

* Look to the attached file

Download docx
4 0
3 years ago
Read 2 more answers
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