The interest earned in 5 years would be $270
<u>Explanation:</u>
Given:
Principal, P = $1800
Rate of interest, r = 3%
Time, t = 5 years
Simple interest, I = ?
We know,
On substituting the value we get
Therefore, interest earned in 5 years would be $270
Using the binomial distribution, it is found that the expected values are given by:
a) 120.
b) 150.
<h3>What is the binomial probability distribution?</h3>
It is the probability of <u>exactly x successes on n repeated trials, with p probability</u> of a success on each trial.
The expected value of the binomial distribution is:
E(X) = np
In this problem, for both items, we consider that the number cube is rolled 180 times, hence n = 180.
Item a:
4 of the 6 possible values are greater than 2, hence p = 4/6 = 2/3.
The expected value is given by:
E(X) = 180 x 2/3 = 120.
Item b:
5 of the 6 values are less than 6, hence p = 5/6.
The expected value is given by:
E(X) = 180 x 5/6 = 150.
More can be learned about the binomial distribution at brainly.com/question/24863377
Segment in the direction from A to C
Initial Point: A=(9,5)=(xa,ya)→xi=xa=9, yi=ya=5
Final point: C=(-7,1)=(xc,yc)→xf=xc=-7, yf=yc=1
B=(xb,yb)=?
Proportion: r=AB/BC=3:1=3/1→r=3
xb=(xi+r*xf)/(1+r)
Replacing xi=xa=9, xf=xc=-7 and r=3
xb=[9+3*(-7)]/(1+3)
xb=(9-21)/4
xb=(-12)/4
xb=-3
yb=(yi+r*yf)/(1+r)
Replacing yi=ya=5, yf=yc=1 and r=3
yb=[5+3*(1)]/(1+3)
yb=(5+3)/4
yb=8/4
yb=2
B=(xb,yb)→B=(-3,2)
Answer: B=(-3,2)
<h3>
Answer: Choice C</h3>
{x | x < -12 or x > -6}
=========================================================
Explanation:
Let's solve the first inequality for x.
(-2/3)x > 8
-2x > 8*3
-2x > 24
x < 24/(-2)
x < -12
The inequality sign flips when we divide both sides by a negative value.
Let's do the same for the second inequality.
(-2/3)x < 4
-2x < 4*3
-2x < 12
x > 12/(-2)
x > -6
The conclusion of each section is that x < -12 or x > -6 which points us to <u>choice C</u> as the final answer.
Side note: The intervals x < -12 and x > -6 do not overlap in any way. There's a gap between the two pieces. We consider these intervals to be disjoint. The number line graph is below.
