What is the volume of the square pyramid with base edges 54 yd and slant height 45 yd?

1 answer:

7 0

The answer is V = 34,992 y^3

You can answer this using an online calculator - calculator soup dot com under geometry then pyramid. Select given a (side length) and s (slant height). Enter the amounts to find V (volume).

To manually compute, get the h (height) first before computing for V (volume).

h^2 = l^2 - (s/2)^2 : l (slant height), s (base edge/side)
h = √((45^2) - (54/2)^2)
h = 36

Then find V (volume) : s (side), h (height)

V = 1/3 (s^2)(h)
V = 1/3 (54^2)(36)
V = 34,992 y^3

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A length of the triangle can be written as according to law of cosines if sides are given and one angle is $a^{2} =b^{2} +c^{2} -2bccos(A)$

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as $p^{2} =6^{2} +8^{2} -2*6*8cos(39)$ .

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Learn more about trigonometric functions at brainly.com/question/24349828

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