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Rasek [7]
3 years ago
9

What is the volume of the square pyramid with base edges 54 yd and slant height 45 yd?

Mathematics
1 answer:
Effectus [21]3 years ago
7 0
The answer is V = 34,992 y^3

You can answer this using an online calculator - calculator soup dot com under geometry then pyramid. Select given a (side length) and s (slant height). Enter the amounts to find V (volume).

To manually compute, get the h (height) first before computing for V (volume).

h^2 = l^2 - (s/2)^2  :  l (slant height), s (base edge/side)
h = √((45^2) - (54/2)^2)
h = 36

Then find V (volume) : s (side), h (height)

V = 1/3 (s^2)(h)
V = 1/3 (54^2)(36)
V = 34,992 y^3

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f(x) = 5x - 4

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f(2a) = 5(2a) - 4

f(2a) = 10a - 4

156 = 10a - 4

10a - 4 = 156

Add sides 4

10a - 4 + 4 = 156 + 4

10a = 160

Divide sides by 10

\frac{10a}{10}  =  \frac{160}{10}  \\

a = 16

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What is the constant of proportionality for m=32•g
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Answer:

∴ Constant of Proportionality is 32

Step-by-step explanation:

Here Given;

m=32\times g  (equation-1)

\frac{m}{g}=32  (equation-2) (divide with 'g' on both side)

We know,

The Constant of Proportionality equation is given;

y=k\times x  (equation-3)

Where 'k' is known as Constant of Proportionality.

Comparing equation-1 and equation-3;

y=m and x=g

Now equation-2 become;

k=\frac{y}{x}

Plug y=m and x=g in above equation;

\frac{m}{g}=k  (equation-4)

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