What is - ( 2)^3?<br><br><br> Help please

Tasya [4]

Answer:

Square

Step-by-step explanation:

The length of AB is (a+b)-a = b. The length of BC is b-0 = b. So, adjacent sides are the same length. AB has a constant y-value, so is horizontal. BC has a constant x-value, so is vertical.

A figure with horizontal and vertical sides of the same length is a square.

7 0

2 years ago

Limit as x approaches 9 of x^2 -81/sqrt of x - 3

Ipatiy [6.2K]

Answer:

108

Step-by-step explanation:

Limit as x approaches 9 of x^2 -81/sqrt of x - 3

First substitute x into the expression

= 9²-81/√9 - 3

= 81-81/3-3

= 0/0 (indeterminate)

Apply l'hospital rule

= lim x -> 9 d/dx(x²-81)/√x - 3

= lim x -> 9 2x/1/2√x

Substitute x = 9

= 2(9)/1/2√9

=18/1/(2(3)

=18 × 6/1

= 108

Hence the limit of the function is 108

7 0

3 years ago

Help anybody? If so thanks

777dan777 [17]

Acute angle and a right angle makes a obtuse I learned this in 4th

4 0

2 years ago

Write an equation of the line satisfying the given conditions. Through (2, -5), parallel to 5x 6y + 7

mojhsa [17]

We have to determine the equation of the line passing through the point (2,-5) and parallel to the line $5x = 6y+7$

When two lines are parallel, then the slopes of the two lines are equal.

Equation of line with point $(x_1, y_1)$ and slope 'm' is given by:

$(y-y_1) = m(x-x_1)$

Since, we have to determine the equation of a line with point (2,-5).

So, the equation of the line is : $(y-(-5)) = m(x-2)$

$y+5 = m(x-2)$

Since, the line is parallel to the line $5x = 6y+ 7$

So, $6y +7 = 5x$

$6y = 5x - 7$

$y = \frac{5}{6}x - \frac{7}{6}$

So, slope of the line 'm' is $\frac{5}{6}$ .

Therefore, the equation of the line is:

$(y+5) = \frac{5}{6}(x-2)$

$6y + 30 = 5x - 10$

$6y - 5x = -10-30$

$6y - 5x = -40$

Therefore, $6y - 5x = -40$ is the required equation of the line.

8 0

2 years ago

The figure shows five points. A point has been translated right and up. Based on the graph, which statements about the points co

REY [17]

If a point is translated right and up, then the image of the point should be to the right and up from the original point, aka the preimage.

Let's go through the choices.

A. Point D could be the image of B.

D is up and to the right of B, so yes. Select choice A

B. Point C could be the image of A.

C is below A, so no

C. Point E could be the image of C.

E is up and to the right from C so yes, Select choice C

D. Point D could be the image of A.

D is down and to the right of A so no.

E. Point E could be the image of B.

E is up and to the right of B so yes. Select choice E

F. Point C could be the image of E.

No C is down and to the left of E.

Answers: A C E

6 0

2 years ago

Read 2 more answers

What is - ( 2)^3? Help please