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nlexa [21]
4 years ago
5

Toya can run one lap of the track on 1 minute 3 seconds, which is 90% of her younger sister niki’s time. What is niki’s time for

one lap of the track?
Mathematics
1 answer:
Alina [70]4 years ago
7 0

63 seconds is 90% of Niki's time for one lap. So, Niki's time for one lap is 63/0.9, which equals 70 seconds or 1 min. 10 seconds.

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Allushta [10]
I think it is 80 yd.
5 0
3 years ago
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At the start of 2014, Mike's car is worth 12000. the car depreciates by 30 percent every year. how much is his car worth in 2017
Anarel [89]

Answer:

$4,116

Step-by-step explanation:

Worth of Mike's car at the start of 2014 = $12,000

If the car is said to depreciates every year by 30% = 30/100 = 0.3

The worth of the car at the start of 2017 is what we are to determine.

This means that the car depreciated by 30% (0.3) for 3 years since 2014 (2017 - 2014 = 3 yrs)

The worth at the start of 2017 would be calculated as follows:

12,000 × (1 - 0.3)³

= 12,000 × (0.7)³

= 12,000 × 0.343

= 4,116

Worth of the car at the start of 2017 would be $4,116

4 0
3 years ago
Please help me !??!!!
iris [78.8K]

Answer:

X =0

Step-by-step explanation:

divide each term by 15 and simp

4 0
3 years ago
Simplify. -10m+2m^4-13m-20m^4
Ulleksa [173]
First one:

you can add -10m and -13m but you can't add -10m and 2m^4 becuase the powers aren't the same so

when adding the like terms
look at the:
powers, (x^3 adds with x^3)
placehloder letter (x adds with x and y adds with y and so on)

-10m+2m^4-13m-20m^4
powers: m^1 and M^4
placeholders: all m


add
-10m-13m+2m^4-20m^4
-23m-18m^4




second one:
when multiplying exponents, you add with like
so if you multipliy
x^2yz^3 times x^4y^2z^2 thne you would get x^6y^3z^5
when multiply with coeficients
2x^2yz^3 times 4x^4y^2z^2=8x^6y^3z^5
so using associative property a(bc)=(ab)c
2/3 times p^4 times y^3 times y^4 times s^5 times 6 times p^2 times s^3
group like terms

(2/3 times 6) times (p^4 times p^2) times (y^3 times y^4) times (s^5 times s^3)
(4) times (p^6) times (y^7) times (s^8)
4p^6y^7s^8

8 0
3 years ago
In ΔHIJ, the measure of ∠J=90°, JH = 81 feet, and HI = 91 feet. Find the measure of ∠I to the nearest degree.
kakasveta [241]

Answer:

63°

Step-by-step explanation:

  • Sin0=\frac{81}{91}
  • x=sin^{-1}(81/91)\\\\
  • = 62.887
  • ≈ 63°

༻﹡﹡﹡﹡﹡﹡﹡༺

hope it helps...

have a great day!!

8 0
3 years ago
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