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liubo4ka [24]
3 years ago
13

Can someone show me how to do this?

Mathematics
1 answer:
Angelina_Jolie [31]3 years ago
4 0
First, you know that 3/4 = .75. Now we can distribute. multipy -10*.75. Then multiply .75*2/5. Add those two answers together to get your final answer. 

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Prove the identity secxcscx(tanx+cotx)=2+tan^2x+cot^2x
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Hello,

sec(x)= \dfrac{1}{cos(x)} \\

cosec(x)= \dfrac{1}{sin(x)} \\

sec(x)*cosec(x)*(tg(x)+cotg(x))=\dfrac{1}{cos(x)}* \dfrac{1}{sin(x)}*( \frac{sin(x)}{cos(x)} +\frac{cos(x)}{sin(x)})\\

= \dfrac{sin^2(x)+cos^2(x)}{sin^2x*cos^2x} \\

= \dfrac{1}{sin^2x*cos^2x} \\


==============================================================
2+tg^2(x)+cotg^2(x)=2+ \dfrac{sin^2x}{cos^2x} + \dfrac{cos^2x}{sin^2x} \\

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= \dfrac{1}{sin^2x*cos^2x}} 

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