For now, let's assume we can rule out choice A.
Angles 3 and 7 are vertical angles. So we can rule out choice B
Angle 3 and angle 11 are corresponding angles. They are on the topside of their adjacent parallel horizontal line. They are also on the left side of the transversal cut line d. The answer is choice C.
Angles 3 and 8 are not corresponding angles. Corresponding angles are not adjacent to one another. In other words, they do not share a common vertex.
The formula for this equation is -6 for each number. So the answer your looking for is 9...3....-3....-9....-15.....-27. Hope I helped you out.
Hello:
Use implicit differentiation : <span>y sin 12x = x cos 2y
y' sin12x+12ycos12x =cos2y -2x y'sin2y
when : x = </span>π/2 and y =π/4<span>
</span>y' sin12(π/2) +12(π/4)cos12(π/2) =cos2(π/4) -2(π/2) y'sin2(<span>π/4)
</span>y' sin(π/6) +(π/3)cos(π/6) =cos(π/2) - π y'sin(π/2)
y' (1/2) +(π/3)(√3/2) = - π
y' (1/2) =-(π/3)(√3/2) - π
y' = -π (1+√3)/3
an equation of the tangent line is : y- π/4 = ( -π (1+√3)/3)(x-<span>π/2)</span>
Is there a formula to this question maybe it will help?
The shaded region's area is x² + 23x + 49.
Step-by-step explanation:
Step 1; To calculate the area of the shaded region, we subtract the area of the square which has side lengths of (x + 1) from the entire rectangle. So we determine the equations that denote the areas of the two shapes.
Step 2; Area of the square = side length × side length (x + 1)×(x + 1) = x² + x + x + 1 = x² + 2x + 1
Area of the bigger rectangle = length × breadth = (x + 10) × (2x + 5) = 2x² + 5x + 20x + 50 = 2x² + 25x + 50.
Step 3; The given shaded region's area = Area of the bigger rectangle - Area of the smaller square = 2x² - x² + 25x - 2x + 50 - 1 = x² + 23x + 49.
So the shaded region's area of x² + 23x + 49.
