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Drupady [299]
3 years ago
10

Does a plane have a definite beginning and end?

Mathematics
1 answer:
Lorico [155]3 years ago
5 0
Technically no.  It extends forever in the X and Y axis, but does not have a Z axis.
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It is 11 a.m. in the Eastern Time Zone; therefore, what time is it in the Pacific Time Zone
lana66690 [7]
Pacific time is 3 hours before Eastern time so subtract 3 hours from 11:00 am and you get 8:00 am
6 0
3 years ago
Answer:<br><br> y=<br> Include no spaces in your answer.
olasank [31]
The answer is y = -2
4 0
3 years ago
Sundas made 2 out of her 5 shots she attempted. Find the percent of the shots she attempted.​
Rudik [331]

Answer:

<u>i think</u> it is 40%

Step-by-step explanation:

she made 2/5 shots so

2/5*2=4/10

i times it by 2 because its out of 100

4/10*10=40/100

then i times it by 10 to get to 100

(2/5 is not 2 divided by five it is 2 over 5 just incase u didnt know what i was talking about)

8 0
2 years ago
List least to greatest <br> -3/8, 5/16, -0.65, 2/4
amid [387]
-0.65
-3/8
2/4
5/16
I hope this is right, the negatives should go first because you are taking away, then positives 
8 0
3 years ago
In the past, the average age of employees of a large corporation has been 40 years. Recently, the company has been hiring older
Viktor [21]

Answer:

p_v =P(t_{(63)}>2.5)=0.0075  

If we compare the p value and the significance level given \alpha=0.05 we see that p_v so we can conclude that we have enough evidence to fail reject the null hypothesis, so we can conclude that the mean age is significantly higher than 45 years at 5% of significance.  

Step-by-step explanation:

1) Data given and notation  

\bar X=45 represent the mean height for the sample  

s=16 represent the sample standard deviation for the sample  

n=64 sample size  

\mu_o =40 represent the value that we want to test

\alpha=0.05 represent the significance level for the hypothesis test.  

t would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the mean age is higher than 40 years, the system of hypothesis would be:  

Null hypothesis:\mu \leq 40  

Alternative hypothesis:\mu > 40  

If we analyze the size for the sample is < 30 and we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:  

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Calculate the statistic

We can replace in formula (1) the info given like this:  

t=\frac{45-40}{\frac{16}{\sqrt{64}}}=2.5    

P-value

The first step is calculate the degrees of freedom, on this case:  

df=n-1=64-1=63  

Since is a one right tailed test the p value would be:  

p_v =P(t_{(63)}>2.5)=0.0075  

Conclusion  

If we compare the p value and the significance level given \alpha=0.05 we see that p_v so we can conclude that we have enough evidence to fail reject the null hypothesis, so we can conclude that the mean age is significantly higher than 45 years at 5% of significance.  

6 0
3 years ago
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