3 years ago

25.9 billion increase by 20%

Mathematics

2 answers:

Gennadij [26K]3 years ago

7 0

226,381 is the answer

stellarik [79]3 years ago

3 0

5,180,000,000

I hope this helps.

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A circle has its center at (0,0) and passes through the point (0,9). What is the standard equation of the circle?

Alexxandr [17]

Answer:

x^2+y^2=9^2

Step-by-step explanation:

The standard equation of a circle is:

$(x-h)^2+(y-k)^2=r^2$

Where the center of a circle is (h,k) and r is the radius of the circle. In this case because a circle is equidistant from the center and we have a point where it passes through 9 that means that the radius is 9. However, since the standard equation states that we must write r in the form of $r^2$ this means that $r^2=9^2$ . Therefore by plugging in the values we have: