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just olya [345]
3 years ago
9

1/6+1/12 Write the Awnser in lowest terms Show your work

Mathematics
1 answer:
Nezavi [6.7K]3 years ago
6 0

Answer:

1/4

Step-by-step explanation:

1/6 + 1/12

Multiply the numerator and denominator of the first fraction by 2.

2/12 + 1/12

Add both fractions, because they have a common denominator.

3/12

The fraction can be further simplified.

1/4

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A population of 200 animals has a growth rate of 1.03% each year. at this growth rate, the function f(x)=200(1.03)^x gives the p
Y_Kistochka [10]
For this case, the first thing we should do is use the following equation:
 f (x) = 200 (1.03) ^ x
 We substitute f (x) = 300:
 300 = 200 (1.03) ^ x
 We clear the value of x:
 log1.03 (300/200) = log1.03 ((1.03) ^ x)
 x = log1.03 (300/200)
 x = 13.72
 Answer: 
 the population will first reach 300 in about 13.72 years.
6 0
2 years ago
Find an approximate equation y=ab^x with the coordinates (0, 4) (3, 95)
bogdanovich [222]
We have y=ab^{x}

Plug in (0, 4):
4=ab^{0}⇒4=a
So we now have a

Plug in (3, 95):
95=4b^{3}
⇒b^{3}=\frac{95}{4}
⇒b=\sqrt[3]{\frac{95}{4}}
which is approximately 2.874

So we get
y=4(\sqrt[3]{\frac{95}{4}})^{x}
or, in decimal form,
y=4*2.874^{x}
7 0
2 years ago
A stone is thrown at an angle of 30° above the horizontal from the top edge of a cliff with an initial speed of 12 m/s. a stop w
stellarik [79]
To solve this problem you must apply the proccedure shown below:
 1. You must apply the following formula:
 yo=-(Voy)t+gt²/2
 2. You have that:
 Voy=VoxSin(30°)
 Voy=(12 m/s)(Sin(30°))
 Voy=6 m/s
 t=5.6 s
 g=9.8 m/s²
 2. When you susbtitute these values into the formula, you obtain:
 yo=-(6 m/s)(5.6 s)+(9.8 m/s^2)(5.6 s)²/2
 yo=120.06 m
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3 0
3 years ago
Can someone help me on this pls? It’s urgent, so ASAP (it’s geometry)
GarryVolchara [31]

<u>Question 6</u>

1) \overline{AB} \cong \overline{BD}, \overline{CD} \perp \overline{BD}, O is the midpoint of \overline{BD}, \overline{AB} \cong \overline{CD} (given)

2) \angle ABO, \angle ODC are right angles (perpendicular lines form right angles)

3) \triangle ABO, \triangle CDO are right triangles (a triangle with a right angle is a right triangle)

4) \overline{BO} \cong \overline{OD} (a midpoint splits a segment into two congruent parts)

5) \triangle ABO \cong \triangle CDO (LL)

<u>Question 7</u>

1) \angle ADC, \angle BDC are right angles), \overline{AD} \cong \overline{BD}

2) \overline{CD} \cong \overline{CD} (reflexive property)

3) \triangle CDA, \triangle CDB are right triangles (a triangle with a right angle is a right triangle)

4) \triangle ADC \cong \triangle BDC (LL)

5) \overline{AC} \cong \overline{BC} (CPCTC)

<u>Question 8</u>

1) \overline{CD} \perp \overline{AB}, point D bisects \overline{AB} (given)

2) \angle CDA, \angle CDB are right angles (perpendicular lines form right angles)

3) \triangle CDA, \triangle CDB are right triangles (a triangle with a right angle is a right triangle)

4) \overline{AD} \cong \overline{DB} (definition of a bisector)

5) \overline{CD} \cong \overline{CD} (reflexive property)

6)  \triangle ADC \cong \triangle BDC (LL)

7) \angle ACD \cong \angle BCD (CPCTC)

8 0
1 year ago
Tina reads at least 30 minutes each day. Write an enequality to show how much Tina reads. T = 30 T &lt; 30 T ≥ 30 T ≤ 30
svp [43]

Answer:

T\geq 30

Step-by-step explanation:

Let

T ----> the number of minutes that Tina read each day

we know that

The word "at least" means "greater than or equal to"

so

The inequality that represent this situation is

T\geq 30

All real number greater than or equal to 30 minutes

7 0
3 years ago
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