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soldier1979 [14.2K]
2 years ago
9

Which line coincides with the line 2y + 3x = 4?

Mathematics
1 answer:
Sophie [7]2 years ago
5 0

Answer:

4

Step-by-step explanation:

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Follow the process of completing the square to solve 2x2 + 8x - 12 = 0.
Rom4ik [11]
Please:  Use "^" to denote exponentiation:  <span>2x^2 + 8x - 12 = 0

Reduce this by div. every term by 2:             </span><span>x^2 + 4x - 6 = 0

Here a=1, b=4 and c = -6.  Square half of b, obtaining (4/2)^2 = 4, and add, and then subtract, this 4 to x^2 + 4x - 6:

</span> x^2 + 4x +4  - 4 - 6 = 0.  Rewrite the square as (x+2)^2, obtaining new equation

(x+2)^2 = 10.  Take the sqrt of both sides:   x+2 = plus or minus sqrt(10).

Finally, solve for x:  x = -2 plus or minus sqrt(10).



8 0
3 years ago
Which equation is graphed in the diagram below ​
Deffense [45]

Answer:

y=2x+2

Step-by-step explanation:

7 0
3 years ago
Find the area of the shaded region.
valentina_108 [34]

Answer:

Area of the circle= π(27.8²)

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Find the coordinates of the point (x,y,z) on the planez=4x+3y+1 which is closest to the origin.
Nataliya [291]
Given plane &Pi; : f(x,y,z) = 4x+3y-z = -1
Need to find point P on &Pi;  that is closest to the origin O=(0,0,0).

Solution:
First step: check if O is on the plane &Pi; : f(0,0,0)=0 &ne; -1 => O is not on &Pi;
Next:
We know that the required point must lie on the normal vector <4,3,-1> passing through the origin, i.e. 
P=(0,0,0)+k<4,3,-1> = (4k,3k,-k)
For P to lie on plane &Pi; , it must satisfy
4(4k)+3(3k)-(-k)=-1
Solving for k
k=-1/26
=>
Point P is (4k,3k,-k) = (-4/26, -3/26, 1/26) = (-2/13, -3/26, 1/26)
because P is on the normal vector originating from the origin, and it satisfies the equation of plane &Pi;
Answer: P(-2/13, -3/26, 1/26) is the point on &Pi; closest to the origin.

8 0
2 years ago
Use distributive property to simplify (m-5)4
Blababa [14]

Answer:

4m-20

Step-by-step explanation:

(m - 5)4 \\  = m \times 4 +  - 5 \times 4 \\  = 4m - 20

8 0
3 years ago
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