Answer:
The height of the wall is 2.7 m.
Explanation:
The number of blocks required = 2450. Each cubical block has a side of 20cm(0.2m).
But, volume = length × width × height.
So that,
the volume of each block = (0.2 × 0.2 ×0.2) ![m^{3}](https://tex.z-dn.net/?f=m%5E%7B3%7D)
= 0.008 ![m^{3}](https://tex.z-dn.net/?f=m%5E%7B3%7D)
The total volume of the blocks to be used = 2450 × 0.008
= 19.6 ![m^{3}](https://tex.z-dn.net/?f=m%5E%7B3%7D)
The window has a measurement of 2.5m ×1m;
its space volume = 2.5m ×1m × 0.4m
= 1.0 ![m^{3}](https://tex.z-dn.net/?f=m%5E%7B3%7D)
The door has a measurement of 2m× 3m;
its space volume = 2m× 3m × 0.4m
= 2.4![m^{3}](https://tex.z-dn.net/?f=m%5E%7B3%7D)
Thus, the window space and door space has a volume = 1.0
+ 2.4![m^{3}](https://tex.z-dn.net/?f=m%5E%7B3%7D)
= 3.4![m^{3}](https://tex.z-dn.net/?f=m%5E%7B3%7D)
Total volume of the wall = length × width × height
⇒ The total volume of the blocks - the window space and door space volume = length × width × height
The wall to be constructed has a length of 15m and width 40cm (0.4m).
So that the height could be determined as,
19.6
- (3.4
) = 15m × 0.4m × height
16.2
= 6
×height
⇒ height = ![\frac{16.2}{6}](https://tex.z-dn.net/?f=%5Cfrac%7B16.2%7D%7B6%7D)
height = 2.7 m
Therefore, the height of the wall is 2.7m.