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Zanzabum
3 years ago
6

The ones with red are the ones I have not done and the ones that I need help with! Due tomorrow plz help!

Mathematics
2 answers:
Anit [1.1K]3 years ago
5 0
5 is 60, 4 plus 7= 11. 11+ 7=18. 18+7= 25 annnddd all the way to the nineth which is 53 +7 = 60
professor190 [17]3 years ago
3 0
3 is wrong. It is 105,000
4) 13/60=0.21666 0.21666*360=78 so 78 degrees
5)sequential difference is 7 and the first term is 4 so 7n-3
6)4x-4=2x-10,2x=-6,x=-3
7)5(4)(5)+4^2=100+16=116
8)(-3,7)
11)a=180-70=110 b=a=110 c=70
12)Sum or angles of a hexagon=(6-2)(180)=720. 720/6=120
13)3/51 because there are only 3 aces in the deck and 51 cards in total
You did 14 wrong. It should be 9/12*144=108
17)First and third. Plug in 0 for x
18)72/9*2=16 72/9*7=56 so 16:56
19)2*3+2*3/2=9
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Find the slope of (1,8) and (-1,-4)
aniked [119]

Answer: slope= 6

Slope intercept equation= y= 6x +2

Step-by-step explanation:

Slope formula: (y2 - y1) ÷ (x2 - x1) > (-4-8) ÷ (-1-1) = -12/-2 or 6

Plug slope (-6) and one coordinate into point slope form: y-1=m (x-1)

where m is slope and (1,8) would be (x,y)

Y-8= 6(x-1) > y-8 = 5x -6 > y= 6x +2

3 0
3 years ago
Find the midpoint of the segment with the following endpoints.<br> (6,3) and (2,7)<br> Please help?
BabaBlast [244]

Answer:

(-4,4)

Step-by-step explanation:

3 0
3 years ago
1/2(4y + 18) + 2 simplified
Vanyuwa [196]

Answer: 2y+11

Step-by-step explanation:

I hope this helps<3

3 0
3 years ago
What is 4-2 5/7 i need this fast pls help
bagirrra123 [75]

Answer:

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Step-by-step explanation:

3 0
3 years ago
The path of a projectile launched from a 20-ft-tall tower is modeled by the equation y = -5x2 + 40x + 20. What is the maximum he
Otrada [13]

Answer:

30.49 m

Step-by-step explanation:

To obtain the maximum height, we solve for the value x when dy/dx = 0.

Since, y = -5x² + 40x + 20

dy/dx = d[-5x² + 40x + 20]/dx

dy/dx = -10x + 40

Since dy/dx = 0,

-10x + 40 = 0

-10x = -40

x = -40/-10

x = 4

Substituting x = 4 into the equation for y, we have

y = -5x² + 40x + 20

y = -5(4)² + 40(4) + 20

y = -5(16) + 160 + 20

y = -80 + 160 + 20

y = 80 + 20

y = 100 ft

Since y is in feet, we convert to meters.

Since 1 m = 3.28 ft, 100 ft = 100 ft × 1 m/3.28 ft = 30.49 m

So, the maximum height, in meters  reached by the projectile is 30.49 m

3 0
3 years ago
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