Answer:
The answer to this question is 19.
Step-by-step explanation:
Given that :
f(x)=13.
f'(x)=3. 1 ≤ x ≤ 3.
Integrate
∫f'(x) dx=∫3 dx
f(x)=3x+c 1 ≤ x ≤ 3.
f(1)= 3+c
c=13-3 =10.
f(x)=3x+10 1 ≤ x ≤ 3.
now ,
f(3)=3(3)+10=19.
So f(3) is at least 19.
Answer:
sorry I can't answer
Step-by-step explanation:
pls thanks me
Probably y = 8x. 56 = 8(7), so that works. Without more data, I couldn't say if it could be something else, so that's what I go with.
Answer:Multiply the denominator on the bottom of the fraction by the whole number you are dividing by.
To divide a fraction by a whole number, multiply the bottom of the fraction by this whole number.
The denominator on the bottom of the fraction is 7.
We will multiply 7 by 2.
7 × 2 = 14 and so, 6 / 7 ÷ 2 = 6 / 14 .
Step-by-step explanation:
Answer:
Step-by-step explanation:
Since G(0) = g(0) = 20, the parabolic graphs of these functions share a y-intercept: (0, 20).
Completing the square puts these equations into vertex form, which simplifies comparisons of the graphs:
G(x) = 2x^2 - 12x + 20 becomes
2(x^2 - 6x + 9 - 9) + 20, or
2(x - 3)^2 - 18 + 20, or 2(x - 3)^2 + 2. Comparing this result to
a(x - h)^2 + k, we see that the vertex is located at (3, 2).
Going through the same process for g(x) 2x^2+12x+20, we get:
g(x) = 2(x + 3)^2 + 2, whose vertex is at (-3, 2).
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