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Zarrin [17]
3 years ago
12

Plz don’t skip this I need help!!!!!!!

Mathematics
2 answers:
MatroZZZ [7]3 years ago
7 0

Answer:

<em>AA similarity postulate</em> establishes that triangles are similar

Galina-37 [17]3 years ago
4 0

Answer:

The side-angle-side

Step-by-step explanation:

SAS (number 3)

:))

have a good day!!!

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Which unit rate is the lowest price per ounce? (5 points)
ELEN [110]

Answer:

B)

Step-by-step explanation:

A 25 ounce bag would cost about 14 cents per oz and the 45 ounce bag would cost about 11 cents per oz

7 0
3 years ago
A parabola has its vertex at (2, 1) and crosses the x-axis at (1,0) anu al l
Y_Kistochka [10]

Answer:

A

Step-by-step explanation:

The equation of a parabola in vertex form is

y = a(x - h)² + k

where (h, k) are the coordinates of the vertex and a is a multiplier

Here (h, k) = (2, 1), thus

y = a(x - 2)² + 1

To find a substitute (1, 0) into the equation

0 = a(1 - 2)² + 1

0 = a + 1 ( subtract 1 from both sides )

a = - 1

Hence

y = - (x - 2)² + 1 or

y = 1 - (x - 2)² → A

7 0
3 years ago
Madelynne hopped 12 times in 15 seconds.What is her speed in hops per minute?
BabaBlast [244]
60 seconds = 1 minute
60/15 = 4

12 hops in 15 seconds is the same as

4 * 12 hops in 4 * 15 seconds, or

48 hops in 60 seconds, and since 60 sec = 1 min, it equals

48 hops per minute.
7 0
4 years ago
Let the marked price be x .if you buy a radio for rs 1350 at 25% discount,find marked price.​
Stella [2.4K]

Step-by-step explanation:

Marked price (MP) = x

Selling Price after discount (SP after discount)

= Rs. 1350

Discount rate = 25%

Now

SP after discount = MP - discount % of MP

1350 = x - 25 % of x

1350 = x - x / 4

1350 = 3x / 4

1350 * 4 =3x

5400 / 3 = x

Therefore x = Rs. 1800

The marked price is Rs. 1800

4 0
3 years ago
Why is it necessary to use the absolute value of the difference when finding the distance on a number line, but not necessary wh
padilas [110]
Remember that the distance on a number line is given by the formula: d=|x_{2}-x_{1}|
where 
d is the distance between the points. 
x_{2} is the second point in the number line.  
x_{1} is the first point in the number line.
Now, suppose we are trying to find the distance between the points -1 and -5; our first point is -1, so x_{1}=-1, and our second point is -5, so x_{2}=-5. Suppose we are going to find the distance between the two point without using absolute value:
d=x_{2}-x_{1}
d=-5-(-1)
d=-5+1
d=-4
Look what we have here, a negative distance! Since distances cannot be negative, we must use absolute value to always get postie distances between two point on a umber line:
d=|x_{2}-x_{1}|
d=|-5-(-1)|
d=|-5+1|
d=|-4|
d=4 

Now, the distance between two coordinates on a plane is given by the formula: d= \sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}
where
d is the distance between the two coordinates
(x_{1},y_{2}) are the coordinates of the first point
(x_{2},y_{2}) are the coordinates of the second point 
Notice that (x_{2}-x_{1})^2 and (y_{2}-y_{1})^2 are squared, so it doesn't matter if we get a negative distance because a negative number raised to an even power (like 2) is always positive; therefore we don't need absolute value in this case because we won't ever get a negative distance. 


7 0
3 years ago
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