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Marina CMI [18]
2 years ago
6

It's number 6?its really hard me and my friends have tried but we just don't know.

Mathematics
1 answer:
Elden [556K]2 years ago
6 0
Let n be the amount of points earned in round 5

the goal of the game is to get zero when you add up the point value from all the rounds.

this means
-9 +3 + (-8)+ 2 +n =0

add up all the given numbers, then see which number(n) is required in order to get zero

any questions?
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X = A 21.6 B 12.9 C 9.1
Artist 52 [7]

Answer:

B: 12.9

Step-by-step explanation:

If A B and C are the alternatives, the answer is B: 12.9

The reason is that the hypotenuse can't be smaller than one of its sides, that eliminates alternative C.

And also, the hypotenuse can't be bigger than segments AC + BC, since the side AC is bigger and AC measures 10.8, the hypotenuse would have to measure < 21.6

Any questions, comment.

6 0
2 years ago
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two years of local internet service cost $6855, including the installation fee of $85. What is the monthly fee?
Artemon [7]
First subtract the installation price:
6855-85= 6,770

Then divide 6,770 by 24(12 months in 1 yr.):
6770/24= $282.08

Your monthly fee is $282.08
5 0
3 years ago
Please help with this!!!!!!!! ASAP
Rom4ik [11]

Answer:

yes

Step-by-step explanation:

4 0
2 years ago
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Spam e-mail containing a virus is sent to 1000 e-mail addresses. After 1 second, a recipient machine broadcasts 10 new spam e-ma
pickupchik [31]

Answer:

Answer explained below

Step-by-step explanation:

Spam e-mail containing a virus is sent to 1000 e-mail addresses. After 1 second, a recipient machine broadcasts 10 new spam e-mails containing the same virus, after which the virus disables itself on that machine. (1) Write a recursive definition (i.e. recurrence relation) to show how many spam emails will be sent out after n seconds. (2) Solve the recurrence relation. (3) How many e-mails are sent at the end of 20 seconds

1.START T=0.....

1000 EMAILS SENT AND RECEIVED BY 1000 M/CS.

T=1.....

EACH OF THE M/C SENDS 10 NEW MAILS ....

.................................

LET M[N] BE THE NUMBER OF MAILS SENT OUT AFTER N SECONDS.

SO , EACH OF THESE M/CS WILL SEND 10 MAILS IN NEXT 1 SECOND.

HENCE NUMBER OF MAILS SENT IN N+1 SECONDS=M[N+1]=

M[N+1]=10*M[N].......................1

THIS IS THE RECURRENCE RELATION.....

2.SOLUTION .....

M[N+1]=10M[N]=10*10M[N-1]=10*10*10M[N-2]=........

M(N+1)=[10^1][M(N)]=[10^2][M(N-1)]=[10^3][M(N-2)]=..........=[10^N][M(1)]=[10^(N+1)][M(0)]

M[N+1]=[10^(N+1)][1000]=[10^(N+1)][10^3]=[10^(N+4)]......................................2

THIS IS THE NUMBER OF MAILS SENT AFTER N+1 SECONDS .....OR ....

M[N]=[10^(N+3)].............................................3

..................IS THE SOLUTION FOR NUMBER OF MAILS SENT AFTER N SECONDS.....

3.AFTER N=20 SECONDS , THE ANSWER IS ....

M[20]=10^(20+3)=10^23

8 0
3 years ago
Read 2 more answers
Can u solve this for me: 72 + 4x = 2x + 82 and please show work
8_murik_8 [283]
The answer is X = 5 because first you have to take away 2x from that side so u minus 2x from 4x that gives u: 72 + 2x = 82 then you have to minus 72 from both sides and that gives you 2x = 10 once you have that you divide both sides by 2 because you want the X by itself and once you get that X = 5. Hope this helped!
8 0
3 years ago
Read 2 more answers
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