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Marina CMI [18]
3 years ago
6

It's number 6?its really hard me and my friends have tried but we just don't know.

Mathematics
1 answer:
Elden [556K]3 years ago
6 0
Let n be the amount of points earned in round 5

the goal of the game is to get zero when you add up the point value from all the rounds.

this means
-9 +3 + (-8)+ 2 +n =0

add up all the given numbers, then see which number(n) is required in order to get zero

any questions?
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For the following exercises, find the average rate of change of the functions from x = 1 to x =2.
VMariaS [17]

Answer:

For the function $f(x)=4 x-3$ the average rate change from x is equal 1 to x is equal 2 is 4 .

Step-by-step explanation:

A function is given f(x)=4x-3.

It is required to find the average rate change of the function from x is 1 to x is 2 . simplify.

Step 1 of 2

A function f(x)=4 x-3 is given.

Determine the function $f\left(x_{1}\right)$ by putting the value of x=1 in the given function.

$$\begin{aligned}&f(1)=4(1)-3 \\&f(1)=1\end{aligned}$$$$f(1)=1$$

Determine the function $f\left(x_{1}\right)$ by putting the value of x is 2 in the given function.

$$\begin{aligned}&f(2)=4(2)-3 \\&f(2)=5\end{aligned}$$

Step 2 of 2

According to the formula of average rate change of the equation $\frac{\Delta y}{\Delta x}=\frac{f\left(x_{2}\right)-f\left(x_{2}\right)}{x_{2}-x_{1}}$

Substitute the value of $f\left(x_{1}\right)$ with, $f\left(x_{1}\right)$ with $3, x_{2}$ with 2 and $x_{1}$ with 1 .

$$\begin{aligned}&\frac{\Delta y}{\Delta x}=\frac{5-1}{1} \\&\frac{\Delta y}{\Delta x}=4\end{aligned}$$

3 0
2 years ago
A map has the scale 1/3inch = 8 miles. If city a and city b are 12 inches apart on my map then how far apart are the city’s in r
Feliz [49]
The equation would be
12 ÷ 1/3 =
12 x 3/1 =
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dangina [55]

Answer:

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Step-by-step explanation:

explanation is in the picture!

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Answer:

A- measure of angle 1 is 53 degrees

Step-by-step explanation:

Just trust me.

4 0
2 years ago
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What is it? I am not sure
earnstyle [38]

Answer: I think its A

Step-by-step explanation: maybe

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