With the help of the <em>area</em> formulae of rectangles and triangles and the concept of <em>surface</em> area, the <em>surface</em> area of the composite figure is equal to 276 square centimeters.
<h3>What is the surface area of a truncated prism?</h3>
The <em>surface</em> area of the <em>truncated</em> prism is the sum of the areas of its six faces, which are combinations of the areas of rectangles and <em>right</em> triangles. Then, we proceed to determine the <em>surface</em> area:
A = (12 cm) · (4 cm) + 2 · (3 cm) · (4 cm) + 2 · (12 cm) · (3 cm) + 2 · 0.5 · (12 cm) · (5 cm) + (5 cm) · (4 cm) + (13 cm) · (4 cm)
A = 48 cm² + 24 cm² + 72 cm² + 60 cm² + 20 cm² + 52 cm²
A = 276 cm²
With the help of the <em>area</em> formulae of rectangles and triangles and the concept of <em>surface</em> area, the <em>surface</em> area of the composite figure is equal to 276 square centimeters.
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Answer:
-1.23 is the correct answer
Step-by-step explanation:
-0.3×4.1 = -1.23 because when multiplying the negative is given to the answer unless there are 2 negatives in which case they cancel out.
The surface area of a cone with circumference base of 24π inches and slant height of 20 inches is 384π inches² in terms of π.
<h3>Surface area of a cone</h3>
surface area = πr(r + l)
where
- r = radius
- l = slant height
Therefore,
l = 20 inches
24π = 2πr
r = 12
Therefore,
surface area = π(12)(12 + 20)
surface area = 12π(12 + 20)
surface area = 12π × 32
surface area = 384π inches²
learn more on surface area here: brainly.com/question/2847956
4 times 29=116 and are you a boy or not a boy
