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3 years ago

Which statement is correct?

Mathematics

2 answers:

Alina [70]3 years ago

7 0

<h3>Answer: </h3>

Option C: (2.06 × 10^-2)(1.88 × 10^-1) > 7.69 × 10^-2 / 2.3 × 10^-5

2.06 × 10^-2 = 206

1.88 × 10^-1 = 18.8

206 × 18.8 = 3,872.8

7.69 × 10^-2 = 769

2.3 × 10^-5 = 230,000

769 ÷ 230000 = ‭0.00334347826086956521739130434783‬

3,872.80 > 0.00334347826086956521739130434783‬

RUDIKE [14]3 years ago

4 0

Answer:

Step-by-step explanation:

(2.06 times 10 Superscript negative 2 Baseline) (1.88 times 10 Superscript negative 1 Baseline) is rounded to 3.9

StartFraction 7.69 times 10 Superscript negative 2 Baseline Over 2.3 times 10 Superscript negative 5 Baseline EndFraction is rounded to 3.3

3.9 > 3.3

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What is the probability of rolling doubles and a sum of 6

alisha [4.7K]

3/6 look at the pic to understand

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3 years ago

If p is the smallest of four integers, what is their sum interms of P

xxMikexx [17]

Answer:

If p is the smallest of n consecutive integers of the same sign than we have p , p+1 , p+2 , … , p+(n−1) ,

So the sum is

∑k=0n−1(p+k)=∑k=0n−1p+∑k=0n−1k=np+n2−n2

Here n=4

So we have 4p+6

And checking

p+(p+1)+(p+2)+(p+3)=4p+6

Note if p=−v

Than you have the same thing as if p=v−n+1 just negative for example 3 consecutive integers the smallest is −5 so the sum is −5+(−4)+(−3)=3×−5+32−32=−15+3=−12

On the other hand:

−(3+4+5)=−(3×3+32−32)=−(9+3)=−12

If p=−v the sum of next v+1 integers is −(∑k=0vk)=−(v2+v2)

Than needs an other v integers to bring it up to 0 again. From there it is

∑k=0hk=h2+h2

Where h=n−(2v+1) .

So recap if p is the smallest of n consecutive integers their sum is

p+(p+1)+(p+2)+…+(p+(n−1))=⎧⎩⎨⎪⎪⎪⎪⎪⎪⎪⎪⎪⎪⎪⎪⎪⎪⎪⎪⎪⎪⎪⎪np+n2+n2−(n|p|+n2+n2)((n−|p|)2+(n−|p|)2)−(|p|p+|p|2+|p|2)((n−|p|)2+(n−|p|)2)n≥0p<0∧n<|p|+1p<0∧|p|<n<2|p|+1p<0∧n>2|p|+1

Step-by-step explanation:

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3 years ago

On a piece of paper, graph y>x-1. Then determine which answer choice

zepelin [54]

The graph that matches the given equation is y≥x-1 is Graph A.

Option: C.

<u>Step-by-step explanation:</u>

The given equation y≥x-1 is a linear inequality equation.

Graphing Linear Inequalities differs from graphing regular linear equations. That is it has certain rules to be followed to draw the graph.

First, rearrange the equation as y in the left and other terms in the opposite side.
Check for the line: y= , y≤ and y≥ comes with straight line where as y< and y> comes with a dotted line.
Shading: If y> greater than or y≥ greater than or equal is present then the space above the line has to be shaded. If y< less than or y≤ less than or equal is present then the space below the line has to be shaded.

For the given equation y≥x-1,

The line will be solid passing through (0,-1) and (3,2) since it has y≥. Also, the region above the line is shaded.

So the graph A is the graph that matches the equation y≥x-1.

8 0

3 years ago

Please help me find out the answer in this picture :)

Y_Kistochka [10]

Answer:

The answer is "d" x= r-p / g

Step-by-step explanation:

First let's get rid of the "p" term on the left-side. After you've done that, you have to get rid of the g term. So you divide the x term by the g-term, you do this to both sides.

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3 years ago

An amusement park has 11 roller coasters. In how many ways can you choose 4 of the roller coasters to ride during your visit to

Vadim26 [7]

4!=4*3*2*1=24
11!=11*10*9*8*7*6*5*4*3*2*1=39916800
7!=7*6*5*4*3*2*1=5040
n choose k
how many ways are there to choose k rollercoasters from n choices?

$\left(\begin{array}{ccc}n\\k\end{array}\right)$ = $\frac{n!}{k!(n-k)!}$

$\left(\begin{array}{ccc}11\\4\end{array}\right)$ = $\frac{11!}{4!(11-4)!}$ = $\frac{39916800}{24(7)!}$ = $\frac{39916800}{24(5040)}$ = $\frac{39916800}{120960}$ =330

330 ways

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4 years ago