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Lynna [10]
3 years ago
13

PLS HELP pq has endpoints at p(-5,4) and q(7,-5).what is the midpoint of pq? what are the cordinates of the point 2/3 of the way

from p to q? what is the length of pq?
Mathematics
1 answer:
lara31 [8.8K]3 years ago
5 0

Answer:

a. (1, -0.5)

b. (-0.2, 0.4)

c. 15 units

Step-by-step explanation:

a. The midpoint of PQ

To calculate this, we use the midpoint formula;

(x,y) = {(x1 + x2)/2 , (y1 + y2)/2}

From the question; (x1,y1) = (-5,4) and (x2,y2) = (7,-5)

So (x,y) = (-5+7)/2 , (4-5)/2 = 2/2, -1/2 = (1,-0.5)

The coordinates of the midpoint of pq is (1,-0.5)

c. Length of pq

Mathematically;

Length = √{(x2-x1)^2 + (y2-y1)^2}

Length = √{(7-(-5))^2 + (-5-4)^2}

Length = √(12)^2 + (-9)^2

Length = √(144 + 81) = √(225) = 15

b. What we will use here is the internal division formula of the section formula;

Mathematically the coordinates can be calculated using the formula;

(x,y) = (mx2 + nx1)/m+ n , (my2 + ny1)/m + n

in this case, m = 2 and n = 3

(x1,y1) = (-5,4)

(x2,y2) = (7,-5)

So substituting these values, we have;

(x,y) = (2(7)+ 3(-5))/(2+3) , 2(-5) + 3(4)/(2+3)

(x,y) = (14 -15)/5 , (-10 + 12)/5

= (-1/5, 2/5) = (-0.2, 0.4)

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This is for algebra 2 can someone tell me if I’m right and can someone explain how do you get a= ?
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Answers:

a = 2

h = 3

k = -3

You have the correct h and k values. Nice work so far.

==========================================================

Explanation:

(h,k) is the vertex. So (h,k) = (3,-3) meaning h = 3 and k = -3

To get the value of 'a', we need to plug in some point on the red graph. Each point is of the form (x,y). We can pick any point we want that isn't the vertex.

Let's pick (0,3) which is the y intercept. I'm picking this because 0 is an easy number to work with

------------

y = a|x-h| + k

y = a|x-3| + (-3) .... plug in the h,k values

y = a|x-3| - 3

3 = a|0-3| - 3 .... plug in (x,y) = (0,3)

3 = a|-3| - 3

3 = a*3 - 3

3 = 3a - 3

3a-3 = 3

3a = 3+3 ... adding 3 to both sides

3a = 6

a = 6/3 ... divide both sides by 3

a = 2

The value a = 2 indicates that the parent function y = |x| has been stretched vertically by a factor of 2. So it is twice as tall as before. Then it has been shifted to place the vertex at (3,-3) as shown in the graph.

------------

You may be wondering why you can't pick on the vertex for (x,y)

Let's see what happens if we use (x,y) = (3,-3)

y = a|x-3| - 3

-3 = a|3-3| - 3 ... plug in (x,y) = (3,-3)

-3 = a|0| - 3 ... uh oh, we get 0 here

-3 = a*0 - 3

-3 = 0 - 3

-3 = -3

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