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3 years ago

I need help solving this problem.

Mathematics

1 answer:

lys-0071 [83]3 years ago

5 0

Answer:

The one on the left has a width of 6 feet. The one on the right has a width of 5 ft.

A. The ratio would be 6/5 ( left over right)

B. Volume is cubed so the ratio of their volumes would be:

6^3 / 5^3 = 216 / 125

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Point A (−3,4) and point C is at (2,−6). Find the coordinates of point B on AC such that the ratio of AB to AC is 4:5.

vampirchik [111]

Answer:

(-7/9, -4/9)

Step-by-step explanation:

i used this formula \left(\frac{m\cdot x_{2}+n\cdot x_{1}}{m+n},\frac{m\cdot y_{2}+n\cdot y_{1}}{m+n}\right) in the desmos calculator and this is the answer i got GL

Hope do will on what you are doing :)

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3 years ago

What is the solution (x, y) to the system of equations shown?

iren2701 [21]

Answer:

Step-by-step explanation:

Glad to help

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3 years ago

a dice cube has 6 sides that are numbered 1-6. If the cube is thrown once, what is the probability of rolling an odd number?

I am Lyosha [343]

Answer:

3/6 or 1/2

Step-by-step explanation:

1, 2, 3, 4, 5, 6

3 odd #s and 3 even #s

3/6 are odd which means 3/6 probability of rolling an odd #

5 0

3 years ago

Read 2 more answers

He wholesale price for a chair is $119. A certain furniture store marks up the wholesale price by25% . Find the price of the cha

viva [34]

Rounded total: $149
Exact total: $148.75
Added Markup: $29.75

7 0

3 years ago

If a six-sided die(1-6) and a ten-sided die(1-10) are rolled simultaneously, then what is the probability of rolling both with a

AnnyKZ [126]

Answer:

$Pr = 0.20$

Step-by-step explanation:

Given

$n_1 = 10$ ---- 10 sided

$n_2 = 6$ --- 6 sided

Required

$P(x_1,x_2 > 4)$

First, list out the sample space

$S = \{(1, 1) (1, 2) (1, 3) (1, 4) (1, 5) (1, 6)(2, 1) (2, 2) (2, 3) (2, 4) (2, 5) (2, 6)$

$(3, 1) (3, 2) (3, 3) (3, 4) (3, 5) (3, 6) (4, 1) (4, 2) (4, 3) (4, 4) (4, 5) (4, 6)$

$(5, 1) (5, 2) (5, 3) (5, 4) (5, 5) (5, 6) (6, 1) (6, 2) (6, 3) (6, 4) (6, 5) (6, 6)$

$(7, 1) (7, 2) (7, 3) (7, 4) (7, 5) (7, 6) (8, 1) (8, 2) (8, 3) (8, 4) (8, 5) (8, 6)$

$(9, 1) (9, 2) (9, 3) (9, 4) (9, 5) (9, 6) (10, 1) (10, 2) (10, 3) (10, 4) (10, 5) (10, 6)\}$

$n(S) = 60$ --- total outcomes

The event that the outcome of both is greater than 4 is:

$x_1,x_2> 4 = \{(5, 5) (5, 6)(6, 5) (6, 6)(7, 5) (7, 6) (8, 5) (8, 6)(9, 5) (9, 6) (10, 5) (10, 6)\}$

$n(x_1,x_2>4) = 12$

So, the probability is:

$Pr = \frac{n(x_1,x_2>4)}{n(S)}$

$Pr = \frac{12}{60}$

$Pr = 0.20$

6 0

3 years ago

I need help solving this problem.​

I need help solving this problem.