1. You want to find factors of 4×(-49) that add to 21. Those would be +28 and -7. Replacing the term 21g with the sum 28g -7g, we get an expression that can be factored by grouping.
... (4g² +28g) + (-7g -49)
... = 4g(g +7) -7(g +7) = (4g-7)(g+7)
2. After you factor out 5, you have 5(64y² -16y -15). As in the previous problem, you're looking for factors of 64×(-15) = -960 that sum to -16. There are 14 factor pairs of 960, so it can take a little bit of effort to find the right pair. That pair is -40 and 24. As in the previous problem you replace the term -16y with the sum -40y +24y and factor by grouping.
... = 5(64y² -40y +24y -15) = 5(8y(8y -5) +3(8y -5))
... = 5(8y +3)(8y -5)
3. False. It is perhaps easiest to check this by multiplying out the offered factors. Doing that gives you 36k² -36k +8k -8. The collected k terms add to -28k, not -44k.
he paid for 2 percent of the total cost of the car
Answer:
assuming you want to get rid of the radical here so, 25/2
Step-by-step explanation:
raise the whole fraction to the second power, and the radical will cancel out, then solve 5^2 which is 25. end up with 25 over 2
No because she runs up yes but she also ran down witch means she went exactly 0
Answer:
a. 0.25
b. 0.50
c. 0.75
Step-by-step explanation:
P(E1) = 0.25
P(E2) = 0.25
P(Es) = 0.25
P(E) = 0.25
a. Since there are 4 outcomes with the same probability of occurring, the probability of E occurring is:
b. The probability of any two outcomes occurring is twice the probability of a single outcome occurring
c. The probability of any three outcomes occurring can be written as 100% minus the probability of the remaining outcome occurring
